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lawyer [7]
3 years ago
13

How could two objects have the same temperature but different thermal energies? One object could have more particles and greater

total kinetic energy. One object could have more particles and lesser total kinetic energy. One object could have more calories. One object could have more heat.
Chemistry
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

One object could have more particles and greater total kinetic energy

Explanation:

The higher the temperature the more the particles. So, when we have high temperature, there is more particles interacting.

Temperature can simply be defined or gotten by taking the average of of the kinetic energy of the particles in the object that is the keywords here are TAKING THE AVERAGE KINETIC ENERGY

Thermal energy is the energy that can be gotten from adding up all the total kinetic energy of the particles in the object. So, the keywords here are; ADDING UP THE TOTAL KINETIC ENERGIES.

So, when two particles of the same temperature have the different thermal energy it means that One object could have more particles and thus having greater total kinetic energy.

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kozerog [31]

Answer:

No

Explanation:

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8 0
3 years ago
Does the result of the calculation in question 3 justify your original assumption that all of the SCN^- is in the form of FeNCS^
Naddik [55]
Fe 3+ + SCN- --> FeSCN 2+ 

<span>.......Fe 3+ .......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>

<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>so, using your Keq, there would be no SCN- or Fe 3+ left.....all would be in the form of FeSCN 2+</span>
5 0
3 years ago
1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

___________________________________

\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

3 0
3 years ago
Matter G has a fixed shape and size. It is a:
agasfer [191]

Answer:

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Explanation:

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