Answer:
The answer is 12.35
Explanation:
From the question we are given that the concentration of 
is 
Generally The rate equation is given as
![K_{w} = [H^{+} ][OH^{-} ]](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%20%5BH%5E%7B%2B%7D%20%5D%5BOH%5E%7B-%7D%20%5D)
and 
the rate constant has a value 
Substituting and making [
] the subject we have
![[OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%20%5D%20%3D%20%5Cfrac%7B1%20%2A%2010%5E%7B-14%7D%7D%7B%5BH%5E%7B%2B%7D%5D%7D%20%3D%20%5Cfrac%7B1%20%2A%2010%5E%7B-14%7D%7D%7B8.1%20%2A10%5E%7B-6%7D%7D%20%3D1.235%20%2A%2010%5E%7B-9%7D)
![[OH ^ {-}] = 1.235 * 10^{-9}M](https://tex.z-dn.net/?f=%5BOH%20%5E%20%7B-%7D%5D%20%3D%201.235%20%2A%2010%5E%7B-9%7DM)
Multiply the value by 
as instructed from the question we have
Answer = 
Hence the answer in 2 decimal places is 12.35
Answer:
the raising atomic number
Explanation:
Elements are listed on the periodic table according to their atomic number.
C. It increases and the pH stays constant.
Answer: The value of the equilibrium constant Kc for this reaction is 3.72
Explanation:
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the given chemical reaction:
The expression for is written as:
![K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E3%5Ctimes%20%5BH_2O%5D%5E1%7D%7B%5BHNO_3%5D%5E2%5Ctimes%20%5BNO%5D%5E1%7D)
Thus the value of the equilibrium constant Kc for this reaction is 3.72
