All categories

3 years ago

Xco3 enter the group number of x

1 answer:

4 0

We know that C has a formal charge of +4 while each O element has a formal charge of -2, therefore the formal charge of X is:

X + 2 – 2 * 3 = 0

X + 2 – 6 = 0

X = 4

So X has a group number of 4.

You might be interested in

what is the temperature in Kelvin of 5.00 moles of nitrogen gas in a 30 L container with a pressure of 4.00 atm

Marianna [84]

The temperature of the nitrogen gas is 292.5 K.

Explanation:

Given that

Moles of Nitrogen, n = 5 mol

Volume, V = 30 L

Pressure, P = 4 atm

Gas Constant, R = 0.08205 L atm mol⁻¹ K⁻¹

Temperature = ? K

We have to use the ideal gas equation,

PV = nRT

by rearranging the equation, so that the equation becomes,

T = $$\frac{PV}{nR}\\$

Plugin the above values, we will get,

T = $$\frac{4 \times 30}{5 \times 0.08205}$

= 292.5 K

So the temperature of the nitrogen gas is 292.5 K.

7 0

3 years ago

In this chemical formula: 3NH4 (ammonium) This chemical formula means there are 3 _____________ ___________, and 4 __________ __

seropon [69]

Answer:

hope it helped you

Explanation:

3 atoms of nitrogen and 4 atoms of hydrogen in each molecule

5 0

3 years ago

what is a mole and why does a mole of magnesium and a mole of carbon weigh different they have the same number of atoms?

timofeeve [1]

~ A mole is a unit of 6*10^23.

~One mole of carbon atoms has a mass of exactly 12 g.

~ Because magnesium atoms each have twice the mass of carbon atoms ( 24Mg compared with 12C), one mole of magnesium has a mass of 24 g.

~ Rather, one mole of any element has a mass in grams that is equal to its relative atomic mass.

8 0

3 years ago

How many atoms of carbon are present in 1.0 g of c6h12o6?

REY [17]

I don't know Im just Trying to get points somehow

4 0

4 years ago

CsH«N2(l) + CuCl(s)

bulgar [2K]

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

Copper(ll) phthalocyanine (Cu(C₃₂H₁₆N₈)) is produced by the cyclotetramerization of phthalonitrile (C₈H₄N₂) according to the following reaction: 4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g) How many moles of copper(II) phthalocyanine would be produced by the complete cyclotetramerization of 255 grams of phthalonitrile in the presence of excess copper(II) chloride?

Let's consider the following balanced equation.

4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g)

The molar mass of C₈H₄N₂ is 128.13 g/mol. The moles corresponding to 255 g of C₈H₄N₂ are:

$255 g \times \frac{1mol}{128.13 g} = 1.99 mol$

The molar ratio of C₈H₄N₂ to Cu(C₃₂H₁₆N₈) is 4:1. The moles of Cu(C₃₂H₁₆N₈) produced from 1.99 moles of C₈H₄N₂ are:

$1.99 mol C_8H_4N_2 \times \frac{1molCu(C_{32}H_{16}N_8)}{4mol C_8H_4N_2} = 0.498 mol Cu(C_{32}H_{16}N_8)$

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

You can learn more about stoichiometry here: brainly.com/question/22288091

8 0

2 years ago