B. a large continent from long ago that eventually broke up into the continents we have today
Answer:
is a class of heavy military ranged weapons built to launch munitions far beyond the range and power of infantry firearms. This development continues today; modern self-propelled artillery vehicles are highly mobile weapons of great versatility generally providing the largest share of an army's total firepower.
Explanation:
it could explode
Answer:
<h3>The answer is 2.75 × 10²⁴ molecules</h3>
Explanation:
The number of molecules of CO2 can be found by using the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 4.56 × 6.02 × 10²³
We have the final answer as
<h3>2.75 × 10²⁴ molecules</h3>
Hope this helps you
Answer:
<h3>
C. MEASURING CYLINDER</h3>
AND PLS BRAINLIEST I REALLY NEED IT THANKS WUV YOU HAHA
Explanation:
<h2>
#BRAINLYEVERYDAY</h2>
Answer:
Explanation:
To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.
Step 1: write out the equation and balance it.
Al+ 3mno2=3mn+ 2Alo3.
The limiting reactant is mn02 because it is not found in excess.
Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8
All=67.2÷100×290(total gram of the reactants)=194.88g
Mno2=32.8÷100×290g=94.12g.
Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.
Mno2=54.938+ (16)2=86.98g/mol.
Mn=54.938.
Step 4:
From your balanced equation , calculate mn.
94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.
94.12g×1÷86.98g×3÷4×54.938÷1
=44.58g
