Easy math questions giving brainlest

I need help ASAP!!! Please explain how to solve the answer.

Pani-rosa [81]

Answer:

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8 0

3 years ago

Which of the following is equal to 4 and 1 over 2 divided by 2 and 2 over 3?

Sphinxa [80]

4 and 1 over 2 times 2 and 3 over 2

4 0

3 years ago

Read 2 more answers

One fourth the sum of x and ten is identical to x minus 4."

Lynna [10]

Answer and Step-by-step explanation:

We are given the word format of an equation.

Let's right it out in numerical form.

$\frac{1}{4} (x + 10) = x - 4$

The first part says One fourth the sum of x and 10

The sum of x and 10 would be shown as x + 10, and one fourth of that means that $\frac{1}{4}$ is multiplying (x + 10).

In this case, identical would mean equal to.

So, $\frac{1}{4}$ (x + 10) would be = to something.

It says that it is identical to x minus 4 (x - 4).

$\frac{1}{4} (x + 10) = x - 4$ is the equation.

#teamtrees #PAW (Plant And Water)

5 0

2 years ago

At 6:00 the outside air temperature was 15°F. By 8:00 the temperature had dropped 9°F, and by 11:00 I had dropped another 12°. W

laila [671]

Answer:

- 6°F

Step-by-step explanation:

Given :

Temperature at 6:00 = 15°F

Temperature dropped by 9°F by 8:00

Temperature by 8:00 = 15°F - 9°F = 6°F

Temperature dropped another 12°F by 11:00

Hence, Temperature at 11:00 will be :

6°F - 12°F = - 6°F

Temperature at 11:00 = - 6°F

8 0

3 years ago

A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored

dem82 [27]

Answer:

Mutually exclusive,

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.

A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

$P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}$

$P(\text{Lemon-lime})=\frac{4}{12}$

$P(\text{Lemon-lime})=\frac{1}{3}$

Let us find probability of finding one orange drink.

$P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}$

$P(\text{Orange})=\frac{4}{12}$

$P(\text{Orange})=\frac{1}{3}$

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

$P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})$

$P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}$

$P(\text{Lemon-lime or orange})=\frac{1+1}{3}$

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Therefore, the probability of choosing a lemon lime or orange is $\frac{2}{3}$ .

8 0

3 years ago