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pogonyaev
4 years ago
15

What is the term for an lon that has more protons than electrons?

Physics
1 answer:
ratelena [41]4 years ago
4 0

Cation

Explanation:

An ion that has more protons than electrons is called a cation.

  • An atom is made up of there fundamental particles.
  • The proton is the positively charged particle in an atom
  • Electron is negatively charged
  • Neutron carry no charges
  • In a neutral atom the number of protons and electrons are equal.
  • In an ion, an electron has either been lost or gained.
  • A cation is a positively charged atom. Here the number of proton is more than that of electrons. In anions, the reverse is the case.

Learn more:

Atom brainly.com/question/4670413

#learnwithBrainly

You might be interested in
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
dimulka [17.4K]

Answer:

The power output of this engine is  P =  17.5 W

The  the maximum (Carnot) efficiency is  \eta_c  = 0.7424

The  actual efficiency of this engine is  \eta _a  = 0.46

Explanation:

From the question we are told that

    The temperature of the hot reservoir is  T_h = 1250 \ K

      The temperature of the cold reservoir  is  T_c  =  322 \ K

     The energy absorbed from the hot reservoir is E_h  = 1.37 *10^{5} \ J

       The energy exhausts into  cold reservoir is  E_c  = 7.4 *10^{4} J

The power output is mathematically represented as

      P  =  \frac{W}{t}

Where t is the time taken which we will assume to be 1 hour =  3600 s  

W is the workdone which is mathematically represented as

      W =  E_h  -E_c

substituting values

       W = 63000 J

So

    P =  \frac{63000}{3600}

    P =  17.5 W

The Carnot efficiency is mathematically represented as

          \eta_c  =  1 - \frac{T_c}{T_h}

         \eta_c  =  1 - \frac{322}{1250}

         \eta_c  = 0.7424

The actual efficiency is mathematically represented as

        \eta _a  =   \frac{W}{E_h}

substituting values

         \eta _a  =  \frac{63000}{1.37*10^{5}}

         \eta _a  = 0.46

     

7 0
4 years ago
What can you conclude about x-rays compared to microwaves?
Alinara [238K]
It is D. X rays have a shorter wavelength than microwaves.
6 0
3 years ago
Read 2 more answers
Solve the following system of equations by using either substitution or elimination.
strojnjashka [21]
I believe that the answer to the question provided above are the following;

x = 29.8410

y = 16.6794

z = -1.2642
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
5 0
3 years ago
An electrician wraps rubber electrical tape around a copper wire. Since rubber is an insulator, which statement best explains th
yuradex [85]

A) Rubber stops charges from flowing. This protects people by stopping electricity from flowing.

Explanation:

The statement that best describes the point of wrapping rubber around the copper wire is that the rubber stops charges from flowing. This prevents people from getting electrical shocks by stopping the flow  of electricity.

  • A rubber is an insulator.
  • Insulators are substances that prevents the flow of electricity.
  • The lack free mobile electrons or ions that makes them conductors.
  • When they are wrapped round a conductor such as copper wire, they will halt the flow of charges.
  • Copper is a conductor of both heat and electricity. It has free mobile electrons.

learn more:

Metals brainly.com/question/2474874

#learnwithBrainly

4 0
4 years ago
Answer the question based on this waveform.
Nuetrik [128]

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

Velocity = 24 m/s

Period = 3 seconds

To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

A is the amplitude.

ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

However, the given parameters can be used to calculate the frequency and wavelength of the wave.

6 0
4 years ago
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