Answer:
The power output of this engine is 
The the maximum (Carnot) efficiency is 
The actual efficiency of this engine is 
Explanation:
From the question we are told that
The temperature of the hot reservoir is 
The temperature of the cold reservoir is 
The energy absorbed from the hot reservoir is 
The energy exhausts into cold reservoir is 
The power output is mathematically represented as

Where t is the time taken which we will assume to be 1 hour = 3600 s
W is the workdone which is mathematically represented as

substituting values

So


The Carnot efficiency is mathematically represented as



The actual efficiency is mathematically represented as

substituting values


It is D. X rays have a shorter wavelength than microwaves.
I believe that the answer to the question provided above are the following;
x = 29.8410
y = 16.6794
z = -1.2642
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.
A) Rubber stops charges from flowing. This protects people by stopping electricity from flowing.
Explanation:
The statement that best describes the point of wrapping rubber around the copper wire is that the rubber stops charges from flowing. This prevents people from getting electrical shocks by stopping the flow of electricity.
- A rubber is an insulator.
- Insulators are substances that prevents the flow of electricity.
- The lack free mobile electrons or ions that makes them conductors.
- When they are wrapped round a conductor such as copper wire, they will halt the flow of charges.
- Copper is a conductor of both heat and electricity. It has free mobile electrons.
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Answer:
Cannot be determined from the given information
Explanation:
Given the following data;
Velocity = 24 m/s
Period = 3 seconds
To find the amplitude of the wave;
Mathematically, the amplitude of a wave is given by the formula;
x = Asin(ωt + ϕ)
Where;
x is displacement of the wave measured in meters.
A is the amplitude.
ω is the angular frequency measured in rad/s.
t is the time period measured in seconds.
ϕ is the phase angle.
Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.
However, the given parameters can be used to calculate the frequency and wavelength of the wave.