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avanturin [10]
2 years ago
6

The nuclues of an atom contains which subatomic particles

Physics
1 answer:
Umnica [9.8K]2 years ago
3 0
Protons and neutrons. Explanation:
Protons are massive, positively charged
nuclear particles.
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A ladder whose length L is 12 m and mass m is 45 kg rests against a wall. Its upper end is a distance h of 9.3 m above the groun
amm1812

Answer:

FN₁ = 1146.6N : Force exerted on the ladder by the floor , vertical and upward

FN₂ = 407.5 N : Force exerted on the ladder by the wall , horizontal and opposite to friction force between the floor and the ladder

Explanation:

The equilibrium equation are:

∑Fx=0

∑Fy=0

∑M = 0  

M = F*d  

Where:  

∑M : Algebraic sum of moments

M : moment  ( N*m)  

F : Force ( N)  

d :Perpendicular distance of the force to the point  ( meters )

Data

m =45 kg  : mass of the ladder

M =72 kg : mass of the fire fighter

g = 9.8 m/s²: acceleration due to gravity

L = 12 m : ladder length

h =  9.3 m: ladder height

L/3 = 12/3 = 4m Location of the center of mass of the ladder of the way up

L/2 = 12/2 = 6m Location of the center of mass of the  fire fighter

µ = 0 : coefficient of friction between the ladder and the wall

θ  : angle that makes  the  ladder  with the floor

sinθ = h/L = 9.3 m/12 m

θ =sin⁻¹( 9.3 / 12)

θ = 50.8°

Forces acting on the ladder

W₁ =m*g = 45 kg* 9.8 m/s² = 441 N: Weight of the ladder (vertical downward)

W₂ =M*g = 72 kg * 9.8 m/s² = 705.6 N : Weight of the fire fighter(vertical downward)  

FN₁ :Normal force that the floor exerts on the ladder (vertical upward)  (point A)

fs : friction force that the floor exerts on the ladder (horizontal and opposite the movement )(point A)  

FN₂ :  Normal Force that the wall exerts on the ladder ( horizontal and opposite to friction force between the floor and the ladder)

∑Fy=0

FN₁ -W₁ -W₂= 0

FN₁ = W₁ + W₂

FN₁ = 441N+ 705.6N

FN₁ = 1146.6N : Force exerted on the ladder by the wall (vertical and upward)

Calculation of the distances of the forces at the point A (contact point of the ladder on the floor)

d₁ = 4*cos 50.8° (m) = 2.53 m:  Distance from W₁ to the point A

d₂ =6*cos 50.8° (m)= 3.79 m  : Distance from W₂ to the point A

d₃ = 9.3 m : Distance from FN₂ to the point A

The equilibrium equation of the moments at the point A  (contact point of the ladder with the floor)  

∑MA = 0  

FN₂(d₃) - W₁( d₁) - W₂(d₂) = 0

FN₂(d₃) = W₁(d₁) + W₂(d₂)

FN₂(9.3) = (441 )(2.53) + (705.6)( 3.79 )

FN₂(9.3) = 1115.73 + 2674.2

FN₂ = (3790) / (9.3)  

FN₂ = 407.5 N : Force exerted on the ladder by the wall , horizontal and opposite to friction force between the floor and the ladder

8 0
4 years ago
Objects 1 and 2 attract each other with a gravitational force
Ivanshal [37]

Answer:

27unit

Explanation:

18×3/2= 9×3= 27unit

3 0
3 years ago
Read 2 more answers
A kid on a playground swing makes 6 complete to-and-fro swings each 30 seconds
Evgesh-ka [11]
I assume that you want to find out what's the frequency is.

Number of oscillation = 6  which being done in 30 second.

which means the time period for 1 oscillation is 30 second/6 = 5 second


Frequency = 1/time period
                 = 1/5 Hertz

Hope this help
4 0
3 years ago
7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colon
skelet666 [1.2K]

The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.

<h3>What is centrifugal force?</h3>

when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.

It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.

The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.

To simulate gravity for the inhabitants, the concept of the centrifugal force is used.

Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.

To learn more about the centrifugal force, refer to the link;

brainly.com/question/17167298

#SPJ1

8 0
3 years ago
A stomp rocket takes 2. 4 seconds to reach its maximum height, what was its initial velocity?.
Anna71 [15]

Answer:

in projectile motion at maximum height v = 0

we can use the suvat equation to find v(initial)

since in this case v(final) is 0

t = 2.4 seconds

we need to find v(initial) or u

v = u+at

u = v- at

in this case a = g (gravity) = -9.81

u = 0 - (-9.81 * 2.4)

u = 9.81 * 2.4

the negatives become positive sin it’s a double negative ( - - = +)

5 0
3 years ago
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