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3 years ago

7

You leave a 3kW heater on in your room. You put it on at 8am and leave it on until 4pm. If a unit (1kWh) costs 12.5p, how much w

ould it cost to leave it on?

1 answer:

natali 33 [55]3 years ago

8 0

Answer:

bpc

Explanation:

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An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density σ1 = -2

pishuonlain [190]

Answer:

$E_{total}=4.82*10^6N/C$

vector with direction equal to the axis X.

Explanation:

We use the Gauss Law and the superposition law in order to solve this problem.

<u>Superposition Law:</u> the Total Electric field is the sum of the electric field of the first infinite sheet and the Electric field of the second infinite sheet:

$E_{total}=E_1+E_2$

<u>Thanks Gauss Law</u> we know that the electric field of a infinite sheet with density of charge σ is:

$E=\sigma/(2\epsilon_o)$

Then:

$E_{total}=(\sigma_1+\sigma_2)/(2\epsilon_o)=(-2.7*10^{-6}+88*10^{-6})/(2*8.85*10^{-12})=4.82*10^6N/C$

This electric field has a direction in the axis perpendicular to the sheets, that means it has the same direction as the axis X.

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The total displacement of the toy car at the given positions is 0.

The given parameters;

<em>First displacement of the car, = 5 cm left</em>
<em>Second displacement of the car, = 8 cm right</em>
<em>Third displacement of the car, = 3 cm to the left</em>

The total displacement of the car is calculated as follows;

<em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
<em>Let the </em><em>right </em><em>direction be "</em><em>positive </em><em>direction"</em>

$\Delta x = - \ 5\ cm \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0$

Thus, the total displacement of the toy car at the given positions is 0.

Learn more about displacement here: brainly.com/question/18158577

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The answer for that would be C

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That only the best traits would go through. The weaker trait in the animals would eventually die off.

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