Answer:
2.5kN.m
Explanation:
Torque is directly proportional to pitch diameter
= Ta/Tb= Da/Db
=120/Tb= 0.25/0.5
Tb= 2.469kN.m approx 2.5kN.m
Answer:
a) v₀ = 69.29 m / s
, b) t = 18.84 s
Explanation:
a) For this exercise we will use the projectile launch equations
x = v₀ₓ t
y = y₀ + 
t - ½ g t²
Let's fix our reference system on the volcano, so the horizontal distance x = 1 km = 1000 m and the vertical distance y = -900 m, the initial height of the crater is I = 0 m. Let's replace to find the speeds
v_{oy} = v₀ sin θ
v₀ₓ = v₀ cos θ
y = v₀ sin θ (x / v₀ cos θ) - ½ g (x / v₀ cos θ)2
y = x tan θ - ½ g x² / v₀² sec² θ
½ g x² sec² θ / v₀² = x tan θ - y
v₀² = ½ g x² sec² θ / (x tan θ –y)
Let's calculate
v₀² = ½ 9.8 1000² sec² 40 / (1000 tan 40 - (-900))
v₀ = √ (8.35 10⁶ / 1,739 10³)
v₀ = 69.29 m / s
b) Flight time
x = v₀ₓ t
t = x / v₀ cos θ
t = 1000 / 69.29 cos 40
t = 18.84 s
The correct answer for the question, "Where should the property "little voltage loss across long distances" be placed in a Venn Diagram?" is : B) alternating current.
A type of current that periodically reverses in direction is called alternating current.
Answer:
because a complete equation must have all the elements present on the left hand side of the arrow on the right hand side of the arrow as well, and to be balanced there must be the same number of each type of atom, so both A and C are full equations, but A is not balanced because although there are two oxygen atoms on each side of the arrow, there is only one hydrogen atom on the left and two on the right, thus the right hand side is 'heavier' than the left and the equation is unbalanced.
Explanation:
Answer:
α = 2Πft + 2Πx/¶
Explanation:
A transverse wave is one of the type of electromagnetic waves which occurs when the vibration of the medium is perpendicular to the direction of the wave. Mathematically, the wave equation according to the question
y1 = Asin(α).... (1)
since its characteristic wave gives a sine wave.
y1 is the vertical displacement
A is the amplitude.
The expression for α of the transverse wave on a string traveling along the positive x-direction in terms of its wavenumber k, the position x, its angular frequency ω, and the time t can be given as;
α = ωt+theta ... (2)
theta is the phase angle. This phase angle is a function of the position x of the wave and the wave number.
theta = kx
where k = 2Πx/¶... (3)
¶ is the wavelength.
ω which is the angular frequency is a function of the frequency (f) of the wave and it is given as;
ω = 2Πf... (4)
Substituting equation 3 and 5 into 2;
α = 2Πft + 2Πx/¶
Therefore,
y1 = Asin(2Πft + 2Πx/¶)
