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soldier1979 [14.2K]
2 years ago
5

Which of the following is an oxidation-reduction reaction? so2(g) h2o(l) right arrow. h2so3(aq) caco3(s) right arrow. cao(s) co2

(g) ca(oh)2(s) h2co3(l) right arrow. caco3(aq) 2h2o(l) c6h12o6(s) 6o2(g) right arrow. 6co2(g) 6h2o(l)
Chemistry
2 answers:
Gennadij [26K]2 years ago
7 0

The reaction which shows oxidation and reduction simultaneously is C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l).

<h3>What are redox reactions?</h3>

Those reaction in which oxidation as well as reduction of substances takes place simultaneously will known as redox reactions.

  • SO₂(g) + H₂O(l) → H₂SO₃(aq)
  • CaCO₃(aq) → CaO(s) + CO₂(g)
  • Ca(OH)₂(s) + H₂CO₃(l)  CaCO₃(aq) + 2H₂O(l)

Above reaction are not the redox reactions as in these reaction oxidation and reduction simultaneously not takes place.

  • C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(l)

In the above reaction reduction of oxygen takes place as its oxidation state changes from 0 to -2, and at the same time oxidation of carbon takes place as its oxidation state changes from 0 to +4.

Hence correct option is (4).

To know more about redox reactions, visit the below link:
brainly.com/question/7935462

expeople1 [14]2 years ago
4 0

Answer:

correct option is (4).

Explanation:

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mel-nik [20]

Answer:

slippery, high pH, and caustic (last option)

Explanation:

when we say base we should think soap. soap is slippery. Bases give OH- ion. when OH- is combined with H+ ion it will create water which raises the pH. Since base can dissolve fats, ex: using dish liquid to cut grease on pots and pans etc.. they are caustic. Biologically they can disrupt the cell memebrane making it caustic to cell tissue.

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3 years ago
The partial charges in this water molecule occur because of _____.
Step2247 [10]
The answer will be because of the unequal sharing of electrons between the hydrogen and the oxygen atoms of a water molecule.

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5 0
3 years ago
What stage includes chromosomes lining up in the center of the cell
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<span>I believe your answer is stage Meiosis.

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4 0
3 years ago
Determinar los números cuánticos del electrón desapareado en el átomo del cloro (Z = 17) y diga si es paramagnético
Musya8 [376]

Answer:

n = 3

l = 1

ml = +1

ms = +1/2

Es paramagnético

Explanation:

Siguiendo las reglas de llenado de orbitales, los 17 electrones del cloro se llenan así:

1S = <u>⇅</u>

2S = <u>⇅</u>

2P = <u>⇅</u> <u>⇅</u> <u>⇅</u>

3S = <u>⇅</u>

3P = <u>⇅</u> <u>⇅</u> <u>↑</u>

<u />

El número cuántico principal n, es el nivel energético donde se encuentra este electrón:

n = 3 (Porque está en el orbital 3P

El número cuántico secundario, l, para el orbital 3P es  = 1:

l = 1

El número cuántico magnético, ml, es determinado por la posición del electrón. Como está en el tercer orbital 3P:

ml = +1

Y el número cuántico de spin, ms (↑ = +1/2; ↓ = -1/2)=

ms = +1/2

Dado que el último electrón se encuentra desapareado, el cloro es paramagnético dado que el espín de el último electrón no tiene su electrón complementario haciendo que este compuesto pueda interactuar con un campo magnético.

3 0
3 years ago
Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct numbe
Lana71 [14]

Answer:

Explanation:

Given the equation:

\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}

The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.

The first step is to determine the algebraic value on the numerator.

Algebraic value = 9.8 - 231

= 7.49

The absolute uncertainty = \sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}

absolute uncertainty = \sqrt{(0.3)^3 + (0.01)^2}

= \sqrt{0.09 + 0.0001}

= 0.300167

∴

[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)

The division process now is:

\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}

Relative uncertainty = \dfrac{(\pm 0.300167)}{7.49}\times 100  \ , \  \dfrac{(\pm 0.6) }{8.5} \times 100

Relative uncertainty = ±4.007565% ,  ±7.058824%

\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}

\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}

\text{Relative uncertainty} = \sqrt{65.88757349}

\text{Relative uncertainty} = 8.117116

≅ 8%

The algebraic value = \dfrac{7.49}{8.5}

= 0.881176

≅ 0.88

The percentage of the relative uncertainty =\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100

By cross multiplying:

\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}

\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}

\text{Absolute uncertainty} (\%) = 0.0715260

\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}

Finally:

\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}

8 0
3 years ago
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