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WITCHER [35]
2 years ago
9

How does a sample of hydrogen at 10 degrees Celsius compare to a sample of hydrogen at 350K?

Chemistry
1 answer:
Sophie [7]2 years ago
8 0

Answer:

We can compare the both sample by taking into account the kinetic energy.

By increasing the temperature kinetic energy of gas molecules increased.

Explanation:

It is known that kinetic energy of molecules is increased by increasing the temperature.

We are given with two sample of hydrogen one is at 10°C and other is at 350 K.

Hydrogen sample at 10°C = 273.15 + 10 = 283.15 k

Thus one sample is at 283.15 K and other is at 350 K. So, the sample at higher temperature i.e 350 K will have more kinetic energy of molecules.

While the sample at 283.15 K will have less speed of molecule and kinetic energy.

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<span>0.0165 m The balanced equation for the reaction is AgNO3 + MgCl2 ==> AgCl + Mg(NO3)2 So it's obvious that for each Mg ion, you'll get 1 AgCl molecule as a product. Now calculate the molar mass of AgCl, starting with looking up the atomic weights. Atomic weight silver = 107.8682 Atomic weight chlorine = 35.453 Molar mass AgCl = 107.8682 + 35.453 = 143.3212 g/mol Now how many moles were produced? 0.1183 g / 143.3212 g/mol = 0.000825419 mol So we had 0.000825419 moles of MgCl2 in the sample of 50.0 ml. Since concentration is defined as moles per liter, do the division. 0.000825419 / 0.0500 = 0.016508374 mol/L = 0.016508374 m Rounding to 3 significant figures gives 0.0165 m</span>
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3 years ago
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Explanation:

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2 years ago
chlorine has two naturally occurring isotopes, Cl-35 and Cl-37. The atomic mass of chlorine is 35.45. Which of these two isotope
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Cl-35, as the atomic mass of Chlorine (35.45) is closer to the number 35 than to the number 37. A higher abundance of CL-35 isotope would have caused the atomic number (which is an average of the values of all isotopes of a substances taking relative abundance into consideration) to decrease from 36, which would appear to be the average.
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3 years ago
Chemistry
postnew [5]

There are 48.72 g  Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%

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\tt 48.72\%\times 200=97.44~g

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\tt =\dfrac{97.44}{2}=48.72~g

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