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yaroslaw [1]
3 years ago
6

How was Aristotle’s model similar to Ptolemy’s model?

Chemistry
2 answers:
Vinvika [58]3 years ago
6 0

The answer is that both models stated that Earth is the center of the system around which other objects orbit.  

That is Aristotle’s model similar to Ptolemy’s model in the way that both stated that Earth is the center of the system around which other objects orbit.  

Ptolemy’s model stated that Earth is the center of universe and other the sun, moon, planets, and stars revolving about it in circular orbits at increasing distance.  

Aristotle’s model stated that the Sun, the Moon, the planets, and the stars travel in different separate spheres. And music of the spheres can be listen when the spheres touch each other. can be heard. He proved that the Earth is spherical,also stated that it is the the center of the universe.

inna [77]3 years ago
6 0

Both models stated that Earth is the center of the system around which other objects orbit.

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How can one determine if a bond between two atoms is ionic covalent or metallic?
Wewaii [24]

Answer:

By the Pauling rule, of EN

Explanation:

EN means electronegativity, the ability of atoms to attract electrons.

In the periodic table each atom, has a value of EN.

When there are two atoms bonded, you must substract the EN (the high - the low) → ΔEN

It depends on the ΔEN, that you can define a bond as ionic, covalent or metallic.

Ionic ΔEN → > 1.7

Covalent polar 0.4 < ΔEN > 1.7

Covalent non polar 0.4 < ΔEN

Two metals have always a metallic bond

5 0
3 years ago
Calculate the specific heat of a substance if a 35g sample absorbs 48 j as the temperature is raised from 293 k to 313 k
bulgar [2K]

Answer:

c = 0.07 j/g.k

Explanation:

Given data:

Mass of sample = 35 g

Heat absorbed = 48 j

Initial temperature = 293 K

Final temperature = 313 K

Specific heat of substance = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

ΔT = 313 k - 293 K

ΔT = 20 k

Now we will put the values in formula.

48 j = 35 g × c× 20 k

48 j = 700 g.k ×c

c = 48 j/700 g.k

c = 0.07 j/g.k

8 0
2 years ago
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