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2 years ago

-(x+23)=34 find x-(2-3)+(2+3)

Chemistry

1 answer:

Elina [12.6K]2 years ago

3 0

this is the answers and working out to both questions

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What is the mass of 0.850 mole of SO2?

Vesnalui [34]

Answer:

$1 \: mole \: of \: sulphurdioxide \: weighs \: 64 \: g \\ 0.850 \: moles \: will \: weigh \: (0.850 \times 64) \: g \\ = 544 \: g$

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2 years ago

Read 2 more answers

On the space shuttle, lithium hydroxide is produced from lithium oxide and water. The lithium hydroxide then reacts with the exh

Ratling [72]

Answer:

6,2g of CO₂

Explanation:

Based on the reactions:

Li₂O(s) + H₂O(g) → 2LiOH(s)

LiOH(s) + CO₂(g) → LiHCO₃(s)

2,6g of Li₂O and 1,3g of H₂O are:

2,6g × ( 1mol / 29,88g) = 0,087 moles

1.3g × ( 1mol / 18,01g) = 0,072 moles

That means limiting reactant is H₂O. The moles produced of LiOH are:

0,072 moles of H₂O × ( 2mol LiOH / 1mol H₂O) =<em> 0,14 moles of LiOH</em>

Thus, the maximum CO₂ that can react are 0,14 moles of CO₂, in grams

0,14 moles CO₂ × (44,01g / 1mol) = <em>6,2g of CO₂</em>

I hope it helps!

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3 years ago

What is the electronegativity difference between oxygen and fluorine? What type of bond is this?

JulijaS [17]

Answer:

Veja, por exemplo, que os elementos mais eletronegativos são os que estão no canto superior direito da tabela, isto é, o flúor (4,0) e o oxigênio (3,5), e os menos eletronegativos são os que estão no canto inferior esquerdo, que são o frâncio (0,8) e o césio (0,8).

Explanation:

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2 years ago

In a redox reaction, what happens to a substance’s charge when it is oxidized?

sammy [17]

I use the acronym LEO for oxidation reactions. This stand for: Lose electrons Oxidation, so when oxidation occurs, electrons are lost. Due to electrons having a negative charge, substance undergoing oxidation have a more POSITIVE charge.

Pls Thank + Branliest its good for my ego :P

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3 years ago

Suppose that 6.2 mL of 2.1 M KOH(aq) is transferred to a 250 mL volumetric flask and diluted to the mark. It was found that 36.9

galina1969 [7]

Answer:

0.928 M

Explanation:

The concentration of acid can be determined by using the volume used and the concentration and volume used of base.

We will use the law of equivalence of moles.

M₁V₁=M₂V₂

M₁ = concentration of base used

V₁ = volume of base used

M₂ = concentration of acid used =? (to be determined)

V₂ = volume of acid used

The initial concentration of KOH used is diluted so let us find the final concentration of KOH after dilution

initial moles = final moles

initial concentration X initial volume = final concentration X final volume

6.2 X 2.1 = 250 X final concentration

final concentration = 0.052 M = M₁

V₁ = 36.9 mL

V₂ = 6.2 mL

Here with each mole of phosphoric acid three moles of KOH are used.

Therefore

3 M₁V₁ = M₂V₂

M₂ = $\frac{V_{2}}{3M_{1}V_{1}}=0.928M$

3 0

3 years ago

-(x+23)=34 find x-(2-3)+(2+3)​

-(x+23)=34 find x-(2-3)+(2+3)