Answer:
100.8 °C
Explanation:
The Clausius-clapeyron equation is:
-Δ
Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'
Isolating for T2 gives:
(sorry for 'deltaHvap' I can not input symbols into equations)
thus T2=100.8 °C
Answer;
The above statement is true
upon heating a copper sample will expand, leading to a lower density
Explanation;
-The density of solids decreased with increase in temperature and vice versa. The increase in temperature causes the volume of the solid to increase which as a result decreases the density as Density=Mass/Volume. The temperature of a body is the average kinetic energy of the molecules present in it.
In other words; The temperature of a body is the average kinetic energy of the molecules present in it. Therefore; when heat is supplied ( or temperature is increased) the average kinetic energy increases which increases the volume and thus density decreases.
Red blood cells is correct
<span>At a depth of 34 feet the diver experiences 2 atmospheres of pressure.
At a depth of 68 feet the diver is experiencing 3 atmospheres.
At a depth of 102 feet the diver is experiencing 4 atmospheres of pressure.
At one atmosphere of pressure the body is mildy compressed. As the diver descends the divers body will undergo increased compression instead of being squashed.</span>
Answer:
0.92 g
Explanation:
Given data:
Percentage of NaCl = 1.6%
Amount of NaCl present in 57.2 g = ?
Solution:
1.6% of 57.2 g NaCl:
1.6/100× 57.2 g
0.92 g
So in 57.2 g 1.6% of NaCl is 0.92 g.
