This is an incomplete question, here is a complete question.
Consider the second-order decomposition of nitroysl chloride:
At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?
Answer : The time needed for NOCl is, 2.52 seconds.
Explanation : Given,
Rate constant =
Initial partial pressure of NOCl = 56 torr = 0.0737 atm
final partial pressure of NOCl = 14.5 torr = 0.0191 atm
The expression used for second order kinetics is:
where,
k = rate constant
t = time
= concentration at time 't'
= initial concentration
As we know that,
Thus, the expression of second order kinetics will be:
As,
So, ............(1)
Now put all the given values in the above expression 1, we get:
Therefore, the time needed for NOCl is, 2.52 seconds.
Answer:
D.
Explanation:
Adding more gas particles to a set volume will increase the number of collisions, thus increasing collision force and pressure.
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