X^2(x+4) x 3x^2(x-1)
(X^3+4x^2) x (3x^3 -3x^2)
3x^6 -3x^5+12x^5 -12x^4
3x^6 +9x^5-12x^4
I think that’s how you do it
2b+h = 4.82
b+2h = 3.70
multiply the second equation by 2:
2b + 4h = 7.40
subtract the first equation from it:
3h = 2.58
h = 0.86
4y = -23 + 39
4y = 16
y = 4
Sub y = 4 into equation 2
7x + 6(4) = -39
7x + 24 = -39
7x = -39-24
7x = -63
x = -9
x = -9
y = 4
Basically you just need to multiply the two fractions together to get the depth of the turtle. Therefore the turtle is 3/12 miles deep or 1/4 mile deep.
