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Dmitrij [34]
3 years ago
5

If an aspirin tablet contains 325mg aspirin, how many grams of aspirin does it contain?

Chemistry
2 answers:
Tomtit [17]3 years ago
5 0

Answer:

0.325 gram

Explanation:

divide the mass value by 1000

amm18123 years ago
4 0

Answer:

It contains 0.325g

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J. Explain how an atom's valence electron configuration determines its place on the periodic table.​
Darya [45]

Answer:

Elements having same valence electrons are placed in <u>same group.</u>

Explanation:

First, let's start with some basic concepts of modern periodic table:

1. Modern Periodic table : It is the arrangement of element in the increasing order of their atomic numbers

The Modern periodic table is divided into Periods and groups .

Periods : These are the horizontal rows. There are seven periods in the periodic table . Period 1 has 2 element. Period two and three has 8 elements , period 4 and 5 have 18 elements and the period 6 and 7 have 32 elements.

Same period have same number of atomic orbital(Shell)

Group : The group is the vertical columns . There are 18 groups in the modern periodic table.Those element which have same group number will also have same number of electron in their outermost shell. The number of electron in the outermost shell determines the valency of the element.

So, elements showing same valency are placed in same group.

All alkali are place in group 1 and have 1 valance electron in the outermost shell

5 0
4 years ago
"how many grams of calcium are consumed when 156.8 ml of oxygen"
Akimi4 [234]
Your question is incomplete. However, I found a similar problem fromanother website as shown in the attached picture.

To solve this problem, you must know that at STP, the volume for any gas is 22.4 L/mol. So,

Moles O₂: 156.8 mL * 1 L/1000 mL* 1 mol/22.4 L = 0.007 moles
Mass calcium: 0.007 mol O₂ * 2 mol Ca/1 mol O₂ * 40 g/mol Ca =<em> 0.56 g Ca</em>

3 0
3 years ago
Please help thank you
Fynjy0 [20]

Answer:

D

Explanation:

8 0
3 years ago
2. A block of aluminum with a mass of 140g is cooled from 98.4oC to 62.2oC with a release of 1137J of heat. From these data, cal
NeTakaya
Q =  M * C *ΔT

Q / <span>ΔT  = M

</span>Δf - Δi =  98.4ºC - 62.2ºC = 36.2ºC
<span>
C = 1137 J / 140 * 36.2

C = 1137 / 5068

C = 0.224 J/gºC</span>
8 0
3 years ago
L = 5 m, w = 1 m, h = 3 m<br><br> 15 m3<br> 5 m2<br> 30 m2<br> 9 m3<br> 7.5 m3
melomori [17]

Volume of Cuboid :

  • l × w × h

  • 5 × 1 × 3

  • 15 m³
6 0
2 years ago
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