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2 years ago

What is 2038 x 28? Giving Brainliest

Mathematics

2 answers:

Papessa [141]2 years ago

4 0

Answer:

57064

Step-by-step explanation:

Alex_Xolod [135]2 years ago

3 0

The answer to your question is ..57064

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Which expression is equivalent to7(a+2)

Vanyuwa [196]

Answer:

7a + 14

just multiply 7 by both a and 2

6 0

3 years ago

Read 2 more answers

Mark decompose 5/6 into three fractions none of them has a denominator of 6 what fractions did mark use

Sliva [168]

Answer:

2/3 + 2/3 + 1/3.

Step-by-step explanation:

You can use equivalent fractions. 6 is 2x more than <u>3</u>. You can use three as the denominator.

5 0

2 years ago

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

Write and solve an equation for the total number of possible combinations from flipping a coin 10 times.

vladimir2022 [97]

Step-by-step explanation:

every flip has 2 possible outcomes.

1 flip has 2.

2 flips have 2×2 = 2² = 4

3 flips have 2×2×2 = 2³ = 8

and so on.

the number of possible combinations flipping a coin n times is

C(n) = 2^n

for 10 flips

C(10) = 2¹⁰ = 1024

possible outcomes or combinations.

5 0

11 months ago

Read 2 more answers

Need help with all questions !!! Get a brainiest answer and a thanks !!

stich3 [128]

1) carrots= 5/12 peas= 2/12 potatoes=1/12
corn= 4/12

2) there are more carrots than peas. there are more corn than potatoes.

3) 2/3

4) separate like number 3 but instead of corn put carrots and leave the peas.

6 0

3 years ago