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3 years ago

Solve for g: 6g = 4 Need help on this problem??

Mathematics

2 answers:

seraphim [82]3 years ago

7 0

6g=4 now divide both sides by 6
g=4/6 simplify
g=2/3

Harman [31]3 years ago

5 0

Remmber you can do anything to an equation as long as you do it to both sides

6g=4
divide both sides by 6
(6g)/6=4/6
(6/6)g=2/3
1g=2/3
g=2/3

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Chau will run at most 28 miles this week. So far, he has run 18 miles. What are the possible numbers of additional miles he will

AysviL [449]

Answer:

Step-by-step explanation:

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3 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

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3 years ago

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A bakery sells ,medium and large pies. The ratio small:medium:large is 3:5:2 .What fraction of the pies are large ?

SOVA2 [1]

2/8

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2 years ago

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kirill115 [55]

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