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Aloiza [94]
2 years ago
11

What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the

box moves is 17m and the force applied is 38 N?
Physics
1 answer:
Jet001 [13]2 years ago
7 0

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

E = (0.4)(38\ N)(17\ m)

<u>E = 258.4 J</u>

Learn more about friction energy here:

brainly.com/question/1343045?referrer=searchResults

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Answer :

(-3.7 meter/second) - (13.9 meter/second) = -17.6 meter/second

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Explanation :

(1) As we are given the expression :

(-3.7 meter/second) - (13.9 meter/second)

Now we have to evaluate this expression, we get:

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8_murik_8 [283]

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The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed
puteri [66]

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Explanation:

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let the average speed of the blood in the capillaries = v₂

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