What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the

Question

2 years ago

11

box moves is 17m and the force applied is 38 N?

1 answer:

Jet001 [13] · Answer 1 · 2023-08-12T12:38:56+03:00

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

$Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd$

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

$E = (0.4)(38\ N)(17\ m)$

Learn more about friction energy here: