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Aloiza [94]
1 year ago
11

What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the

box moves is 17m and the force applied is 38 N?
Physics
1 answer:
Jet001 [13]1 year ago
7 0

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

E = (0.4)(38\ N)(17\ m)

<u>E = 258.4 J</u>

Learn more about friction energy here:

brainly.com/question/1343045?referrer=searchResults

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3 years ago
Two coils of wire are placed close together. Initially, a current of 3.04 A exists in one of the coils, but there is no current
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Answer:

M=0.0247H

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Which of the following best describes what muscles do.
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8 0
2 years ago
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What is the wavelength of a wave with a frequency of 262 hz and a speed of 343 m/s
Tamiku [17]

Heya!!

For calculate wavelength, lets applicate formula:

                                                      \boxed{\lambda = V/f}

                                                   <u>Δ   Being   Δ</u>

                                            f = Frequency = 262 Hz

                                            v = Velocity = 343 m/s

                                             \lambda = Wavelenght = ?

⇒ Let's replace according the formula:

\boxed{\lambda = 343\ m/s / 262\ Hz }

⇒ Resolving

\boxed{\lambda = 1,3 \ m}

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Good Luck!!

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