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Aloiza [94]
1 year ago
11

What is the change in thermal energy E if the coefficent of kinetic friction between the box and floor is .4 , the distance the

box moves is 17m and the force applied is 38 N?
Physics
1 answer:
Jet001 [13]1 year ago
7 0

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

E = (0.4)(38\ N)(17\ m)

<u>E = 258.4 J</u>

Learn more about friction energy here:

brainly.com/question/1343045?referrer=searchResults

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bogdanovich [222]

Answer:

D.vibrations that cause changes in air pressure

Explanation:

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3 years ago
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andreev551 [17]

Answer:

v = 15.8 m/s

Explanation:

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Let's write the mechanical energy at each point

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    Em₀ = Ke = ½ k x²

Final

   Em_{f} = K + U = ½ m v² + mg y

Let's use Hooke's law to find compression

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Let's write the energy equation

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Let's clear the speed

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   v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50)   2/60.0

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From the question;

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