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NeTakaya
2 years ago
6

Which separation method would be most successful in separating the components of a homogeneous mixture? screening evaporation ce

ntrifugation magnetic separation
Physics
2 answers:
ohaa [14]2 years ago
3 0
Filtering the homogeneous mixture to get the materials out and boil away any water
lesantik [10]2 years ago
3 0

Answer:  <u>Evaporation</u>

<u>Explanation:</u>

A homogeneous mixture contains components in same proportion through out the sample.

<u>screening: </u>It is the filtration method for non-homogeneous mixture having different particles size.

Evaporation: It is a method of separation for homogeneous mixture of soluble solute from a solvent.

<u>centrifugation: </u>It is a method of separation for non-homogeneous mixture having different densities.

<u>magnetic separation: </u>It is a method of separation for non-homogeneous mixture having a component with magnetic properties.

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<span>Jupiter is composed almost entirely of gases and liquids, mostly C. hydrogen and helium.</span>
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3 years ago
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Two glass marbles (1 and 2), each supported by a nylon thread, are rubbed against a piece of silk and then are placed near a thi
iragen [17]

Answer:

d.) Marbles 1 and 2 repel each other, but no interaction occurs with marble

Explanation:

Rubbing the glass against the silk charges the glass positively.

Assuming polarization is ignored,

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●neutral objects won't distribute it's charge when affected by charge objects in proximity. Therefore, over the marble surface, the charge remain spherically symmetrical (undisturbed)

Marble 1 is positive

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D is the answer.

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3 years ago
The gravitational pull between Pluto and the sun would be increased if
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2 years ago
A solid sphere has a temperature of 614 K. The sphere is melted down and recast into a cube that has the same emissivity and emi
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Answer:581.87 K

Explanation:

Given

Sphere is melted to form a square

Let the radius of sphere be r and square has a side a

Therefore

\frac{4\pi}{3}r^3=a^3

Surface area of sphere A_s=4\pi r^2

Surface area of cube A_c=6a^2

Total emmisive remains same

Thus P=A\epsilon \sigma T^4

A_sT_s^4=A_cT_c^4

\frac{T_c^4}{T_s^4}=\frac{A_s}{A_c}

\frac{T_c^4}{T_s^4}=\frac{1}{2}\times \left ( \frac{4\pi}{3}\right )^{\frac{1}{3}}

\frac{T_c}{T_s}=\frac{1}{2^{0.25}}\times \left ( \frac{4\pi}{3}\right )^{\frac{1}{12}}

T_c=T_s\times \frac{1}{2^{0.25}}\times \left ( \frac{4\pi}{3}\right )^{\frac{1}{12}}

T_c=614\times \frac{1.12679}{1.189}

T_c=581.87 K

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3 years ago
A swimmer is capable of swimming at 1.4m/s in still water. a. How far downstream will he land if he swims directly across a 180m
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