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2 years ago

6

Which separation method would be most successful in separating the components of a homogeneous mixture? screening evaporation ce

ntrifugation magnetic separation

2 answers:

ohaa [14]2 years ago

3 0

Filtering the homogeneous mixture to get the materials out and boil away any water

lesantik [10]2 years ago

3 0

Answer: <u>Evaporation</u>

<u>Explanation:</u>

A homogeneous mixture contains components in same proportion through out the sample.

<u>screening: </u>It is the filtration method for non-homogeneous mixture having different particles size.

Evaporation: It is a method of separation for homogeneous mixture of soluble solute from a solvent.

<u>centrifugation: </u>It is a method of separation for non-homogeneous mixture having different densities.

<u>magnetic separation: </u>It is a method of separation for non-homogeneous mixture having a component with magnetic properties.

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Compute the dot product of the vectors u and v, and find the angle between the vectors. Bold v equals 7 Bold i minus Bold j and

OLga [1]

Answer:

$\theta = 106.3 degree$

Explanation:

As we know that

$\vec w = -\hat i + 7\hat j$

$\vec v = 7\hat i - \hat j$

also we know that

$\vec v. \vec w = -14$

it is given as

$\vec v. \vec w = (-\hat i + 7\hat j).(7\hat i - \hat j)$

$\vec v. \vec w = - 7 - 7 = -14$

also we can find the magnitude of two vectors as

$|v| = \sqrt{(-1)^2 + (7)^2}$

$|v| = \sqrt{50}$

similarly we have

$|w| = \sqrt{(7^2) + (-1)^2}$

$|w| = \sqrt{50}$

now we know the formula of dot product as

$\vec v. \vec w = |v||w| cos\theta$

$-14 = (\sqrt{50})^2cos\theta$

$\theta = cos^{-1}(\frac{-14}{50})$

$\theta = 106.3 degree$

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3 years ago

Which of the following is NOT a layer of the Sun?

Alja [10]

It depends when you look at a pichture it could possibly help.

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3 years ago

A spearfisher stands in shallow water and sees a fish a few feet in front of her. She throws her spear directly toward the posit

DENIUS [597]

Answer:

the spear will end up above the fish relative to the actual position of the fish.

Explanation:

due to refraction of light coming from the fish the fish will appear slightly above from its real position

So due to this refraction the spearfisher will throw the spear directly at the image of the fish due to which it will not reach the position of fish but it will reach the position above the fish.

So here we can say that the spear will end up above the fish relative to the actual position of the fish

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3 years ago

Given that water at standard pressure freezes at 0∘C, which corresponds to 32∘F, and that it boils at 100∘C, which corresponds t

barxatty [35]

Answer:

In two significant figure 360K

Explanation:

The temperature difference (ΔT) can be calculated as the boiling temperature minus the freezing temperature in Fahrenheit.

Hence,

ΔT = 212 - 32

ΔT = 180°F

To convert to °F to kelvin, we use the formula below

= (°F - 32) × 5/9 + 273.15

= (180°F - 32) × 5/9 + 273.15

= 355.37K ⇔ 360K

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3 years ago

Two trains A and B of length 400 m each are moving on two parallel tracks with

Vinvika [58]

<u>Answer:</u>

<em>The initial distance between the trains is 1450 m. </em>

<u>Explanation:</u>

In the question two trains are of equal length 400 m and moves at a uniform speed of 72 km/h. train A is moving ahead of train B. If the train B has to overtake train A it should accelerate.

Train B’s acceleration is $1m/s^2$ and it accelerated for 50 seconds.

<em> $a=1 m/s^2$ </em>

<em>t=50 s </em>

<em>initial speed u=72km/h </em>

<em>we have to convert this speed into m/s </em>

<em> $u=72 \times 5/18=20 m/s$ </em>

<em>Distance covered in accelerating phase $S=ut+1/2 at^2$ </em>

<em> $=20 \times 50+1/2 \times 1 \times 50^2$ </em>

<em> $=1000+1250=2250 m$ </em>

If a train is just behind another, the distance covered by the train located behind during overtaking phase will be equal to the sum of the lengths of the trains.

<em>Here length of train A+length of train $B=400+400=800 m$ </em>

<em>Hence the initial distance between the trains = $2250-800=1450 m$ </em>

6 0

3 years ago