Step-by-step explanation: It should be the second answer.
Step-by-step explanation: You have to substitute the numbers in for x & y
(0, -5): YES
3x - 4y - 8 = 12
3(0) - 4(-5) - 8 = 12
0 + 20 - 8 = 12
20 - 8 = 12
12 = 12
(4, -2): YES
3x - 4y - 8 = 12
3(4) - 4(-2) - 8 = 12
12 + 8 - 8 = 12
20 - 8 = 12
12 = 12
(8, 2): NO
3x - 4y - 8 = 12
3(8) - 4(2) = 12
24 - 8 = 12
16 = 12
(-16, -17): YES
3x - 4y - 8 = 12
3(-16) - 4(-17) - 8 = 12
-48 + 68 - 8 = 12
20 - 8 = 12
12 = 12
(-1, -8): NO
3x - 4y - 8 = 12
3(-1) - 4(-8) = 12
-3 + 32 = 12
29 = 12
(-40, -34): NO
3x - 4y - 8 = 12
3(-40) - 4(-34) - 8 = 12
-120 + 136 - 8 = 12
16 - 8 = 12
8 = 12
Hope this help you!!! :)
A = (1/2)(b * h)
It is 1/2 times the product (which is the end result of multiplication of two values), of base (b) times height (h)
Answer:
63m^11 no^12
Step-by-step explanation:
Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation
(7nm^5 o^2) × (-3m^3 o^5)^2
7m^5 no^2) ×(-3m^3 o^5) ^2
(7m^5 no^2) × (3m^3 o^5)^2
7m^5 no^2 × (3m^3 o^5) ^2
7m^5 no^2 × 9m^6 o^10
63m^11 no^12