Question

A bag contains 1 blue, 2 green, and 2 red marbles. You choose a marble with one hand and then a second marble with the other hand. What is the probability that you will first choose a red marble followed by a green marble?

Answer 1

The probability that you will first choose a red marble followed by a green marble is 20%.

Probabilities

Given that a bag contains 1 blue, 2 green, and 2 red marbles, and you choose a marble with one hand and then a second marble with the other hand, to determine what is the probability that you will first choose a red marble followed by to green marble the following calculation must be made:

• 1 + 2 + 2 = 5
• 2/5 x 2/4 = X
• 0.4 x 0.5 = X
• 0.2 =X
• 0.2 x 100 = 20

Therefore, the probability that you will first choose a red marble followed by a green marble is 20%.

Learn more about probability in brainly.com/question/26677483

Answer 2

The probability of choosing a red marble is 2/5 while the probability of choosing a green marble after a red marble is 1/2

Data;

• blue = 1
• green = 2
• red = 2

Probability without replacement

To solve this problem, we have to do probability without replacement.

The total number of marbles in the bag is

$1 + 2 + 2 = 5$

The probability of choosing a red marble is

Number of read marbles = 2

probability of choosing a red marble is

$P = \frac{2}{5}$

The probability of choosing a green marble after a red marble is

$P = \frac{2}{4} =\frac{1}{2}$

The probability of choosing a red marble is 2/5 while the probability of choosing a green marble after a red marble is 1/2

Learn more on probability here;

brainly.com/question/251701