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amid [387]
2 years ago
7

A bag contains 1 blue, 2 green, and 2 red marbles. You choose a marble with one hand and then a second marble with the other han

d. What is the probability that you will first choose a red marble followed by a green marble?
Mathematics
2 answers:
katrin2010 [14]2 years ago
6 0

The probability that you will first choose a red marble followed by a green marble is 20%.

<h3><u>Probabilities</u> </h3>

Given that a bag contains 1 blue, 2 green, and 2 red marbles, and you choose a marble with one hand and then a second marble with the other hand, to determine what is the probability that you will first choose a red marble followed by to green marble the following calculation must be made:

  • 1 + 2 + 2 = 5
  • 2/5 x 2/4 = X
  • 0.4 x 0.5 = X
  • 0.2 =X
  • 0.2 x 100 = 20

Therefore, the probability that you will first choose a red marble followed by a green marble is 20%.

Learn more about probability in brainly.com/question/26677483

zhuklara [117]2 years ago
5 0

The probability of choosing a red marble is 2/5 while the probability of choosing a green marble after a red marble is 1/2

Data;

  • blue = 1
  • green = 2
  • red = 2

<h3>Probability without replacement</h3>

To solve this problem, we have to do probability without replacement.

The total number of marbles in the bag is

1 + 2 + 2 = 5

The probability of choosing a red marble is

Number of read marbles = 2

probability of choosing a red marble is

P = \frac{2}{5}

The probability of choosing a green marble after a red marble is

P = \frac{2}{4} =\frac{1}{2}

The probability of choosing a red marble is 2/5 while the probability of choosing a green marble after a red marble is 1/2

Learn more on probability here;

brainly.com/question/251701

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Use the Euclidean Algorithm to demonstrate that 621 and 82 are relatively prime to each other. Explain.
8090 [49]

Answer:

621 and 82 are relatively prime.

Step-by-step explanation:

Two integers are relatively prime (or coprime) if there is no integer greater than one that divides them both (that is, their greatest common divisor is one).

The greatest common divisor of two integers <em>a</em> and <em>b</em> is the largest integer that divides them both.

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

<em>Given integers a, b find </em>d=gcd(a,b)<em />

The Euclidean algorithm provides a fast way to determine <em>d</em> without knowing the prime factors of <em>a</em> or <em>b</em>. Here is an outline of the steps:

  1. Let a=x, b=y
  2. Given <em>x</em>, <em>y</em>, use the division algorithm to write x=yq+r, \quad 0\leq r\leq |y|.
  3. If r = 0, stop and output <em>y</em>; this is the gcd of a, b.
  4. If r \neq 0, replace (<em>x, y</em>) by (<em>y, r</em>). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly until we get a result that lies between 0 (inclusive) and D (exclusive) and is the smallest non-negative number obtained by repeated subtraction.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

Applying the above steps,

621-82=539\\539-82=457\\457-82=375\\375-82=293\\293-82=211\\211-82=129\\129-82=47\\\\621=82\cdot7+47

621 = 82\cdot 7 + 47\\ 82 = 47\cdot 1 + 35\\ 47 = 35\cdot1 + 12\\ 35 = 12\cdot2 + 11\\ 12 = 11\cdot1 + 1\\ 11 = 1\cdot11 + 0

The gcd(621, 82) is 1. Therefore, 621 and 82 are relatively prime.

5 0
3 years ago
Find the solution of this system of equations<br> -4y = -64 - 6x<br> 4x - 4y = -36
blagie [28]

The solution of system is x=14, y=37

Step-by-step explanation:

Given equations are:

-4y = -64 - 6x  => 6x-4y=-64     Eqn 1

4x - 4y = -36     Eqn 2

Subtracting equation 2 from eqn 1

(6x-4y)-(4x - 4y) = -36+64\\6x-4y-4x+4y=28\\2x=28\\Dividing\ both\ sides\ by\ 2\\\frac{2x}{2}=\frac{28}{2}\\x=14\\Putting\ x=14\ in\ equation\ 1\\-4y=-64-6(14)\\-4y=-64-84\\-4y=-148\\Dividing\ both\ sides\ by\ -4\\\frac{-4y}{-4}=\frac{-148}{-4}\\y=37

The solution of system is x=14, y=37

Keywords: Linear equation, Elimination method

Learn more about linear equations at:

  • brainly.com/question/4706270
  • brainly.com/question/4710621

#LearnwithBrainly

4 0
3 years ago
you should have $16 and a coupon for a $5 discount at a local supermarket. a bottle of olive oil costs$7. how many bottles of ol
natta225 [31]
Each bottle costs seven dollars. Two of them would cost $14 and three would cost $21. Buying three bottles, the amount is $21 which exceeds $16. Therefore, a $5 discount will be given. Subtracting $5 from the $21 will give $16. You have just enough amount to buy THREE bottles of olive oil. 
4 0
3 years ago
Exterior Angles of A Triangle
gladu [14]
The exterior angle is supplementary to the adjacent angle (they form a linear pair) and is the sum of the two angles in the triangle that are not adjacent to it. For example, in number 2, the exterior angle is 28+40=68 degrees. You can use the other method to check. 68 degrees is supposed to be in a linear pair with 112 degrees, which it is. So the answer to number 2 would be 68 degrees.

Try doing this for the rest of them
7 0
3 years ago
Question 5(Multiple Choice Worth 1 points) (03.03 LC) If a figure has been dilated by a scale factor of 4, which statement expla
Novosadov [1.4K]

Answer:

A translation can map one angle unto another since dilations preserve angle measures of triangles

Step-by-step explanation:

The dilation of the figure by a scale factor of 4 gives an image that is 4 times the size of the original figure. However, the interior angles of the image and the original figure remain the same

A translation is a rigid transformation, such that the image and the preimage of a translation transformation have the same dimensions and angles

A translation of three consecutive non-linear points of the dilated image to the vertex and the two lines joining the corresponding point on the image, translates the angle at the given vertex

The above process can be repeated, to translate a second angle from the image to the preimage, from which it can be shown that the two figures are similar using Angle Angle, AA, similarity postulate

8 0
3 years ago
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