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amid [387]
2 years ago
7

A bag contains 1 blue, 2 green, and 2 red marbles. You choose a marble with one hand and then a second marble with the other han

d. What is the probability that you will first choose a red marble followed by a green marble?
Mathematics
2 answers:
katrin2010 [14]2 years ago
6 0

The probability that you will first choose a red marble followed by a green marble is 20%.

<h3><u>Probabilities</u> </h3>

Given that a bag contains 1 blue, 2 green, and 2 red marbles, and you choose a marble with one hand and then a second marble with the other hand, to determine what is the probability that you will first choose a red marble followed by to green marble the following calculation must be made:

  • 1 + 2 + 2 = 5
  • 2/5 x 2/4 = X
  • 0.4 x 0.5 = X
  • 0.2 =X
  • 0.2 x 100 = 20

Therefore, the probability that you will first choose a red marble followed by a green marble is 20%.

Learn more about probability in brainly.com/question/26677483

zhuklara [117]2 years ago
5 0

The probability of choosing a red marble is 2/5 while the probability of choosing a green marble after a red marble is 1/2

Data;

  • blue = 1
  • green = 2
  • red = 2

<h3>Probability without replacement</h3>

To solve this problem, we have to do probability without replacement.

The total number of marbles in the bag is

1 + 2 + 2 = 5

The probability of choosing a red marble is

Number of read marbles = 2

probability of choosing a red marble is

P = \frac{2}{5}

The probability of choosing a green marble after a red marble is

P = \frac{2}{4} =\frac{1}{2}

The probability of choosing a red marble is 2/5 while the probability of choosing a green marble after a red marble is 1/2

Learn more on probability here;

brainly.com/question/251701

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