CO + 2 H2 → CH3OH
<span> find # of mols in each reactants, </span>
<span>152500 g CO x 1 mol CO / 28.01g CO = 5444 mol CO </span>
<span>24500 g H2 x 1 mol H2 / 2.02 g H2 = 12129 mol H2 </span>
<span>mol ratio between CO and H2 is 1:2, which means each mol of production of CH3OH need 1 mol of CO and 2 mol of H. </span>
<span>H2 is enough to produce 6064 mols of CH3OH but there are only 5444mol of CO. </span>
<span>5444 mol CH3OH x molar mass of CH3OH / 1 mol CH3OH </span>
<span>= 174371 g = 174.4 kg</span>
It would be the ability to rust because matter takes up space.
Sodium - Na is a neutral atom with 11 protons and 11 electrons.
protons are positively charged and electrons are negatively charged. Since the number of protons and electrons are equal, there are equal amounts of both positive and negative charges therefore they cancel out giving Na an overall neutral charge.
Na has 1 electron in the outermost energy shell, to become stable and to gain a noble gas configuration it loses the electron in its outermost shell.
Once it loses its electron, there are 11 protons and 10 electrons, having an overall positive charge of +1. Once atoms lose or gain electrons they become ions, since Na loses electrons its called a cation.
So in Na⁺, +1 stands for the net charge of the ion which is +1 or in other words Na has just lost one electron therefore is +1 positively charged
Iron becomes rusted especially in damp air but never in a dry air, this is one of the many unique characteristics of iron. Iron is also ductile and malleable. It is found in the seventh group of the periodic table. It has four different and unique crystalline forms and completely dissolves in dilute acids. The two chemical compounds that can be found or made from iron are the bivalent iron also known as ferrous and the trivalent iron or known as ferric compounds.
Answer:
Explanation:
The chemical equation is
For simplicity, let's rewrite this as
1. Initial concentration of NH₃
2. Calculate [OH]⁻
We can use an ICE table to do the calculation.
B + H₂O ⇌ BH⁺ + OH⁻
I/mol·L⁻¹: 0.100 0 0
C/mol·L⁻¹: -x +x +x
E/mol·L⁻¹: 0.100 - x x x
Check for negligibility:
\
3. Solve for x
4. Calculate the pH