The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.
The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.
It can be found using the formula,
m = Z I t
where, m = mass of metal deposited = 75.8g
Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001
I is the current passed
t is the time taken = 75hour = 75 × 60 = 4500s
On subsituting in above formula,
75.8 = E I t / F
⇒ 75.8 = 0.0001 × I × 4500
⇒ I = 168.4 Ampere (A)
Hence, amount of current required to deposit a metal is 168.4A.
Learn more about Law of Equivalence here, brainly.com/question/13104984
#SPJ4
Actually Welcome to the Concept of the Astrophysics.
Let's categorize them eventually ==>
1.) Earth ==> 1.) travels around the Sun
2.) takes 365.25 days .
2.) Moon ===> 1.) travels around the Earth
2.) Takes 27.3 days.
Al₂O has a higher percentage of aluminium.
Explanation:
To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:
Molar mass of Al₂O = 2(27) + 16 = 70g/mol
Molar mass of Al(NO₃)₃ = 27 + 3[14 + 3(16)] = 213g/mol
Percentage by mass of Al in Al₂O = 
x 100 = 77%
Percentage by mass of Al in Al(NO₃)₃ = 
x 100 = 12.7%
Al₂O has a higher percentage of aluminium.
learn more:
Molar mass brainly.com/question/2861244
#learnwithBrainly
25m³.
500mL = 500cm³
25m³ = 2,500cm³
5.5x9 = 49.5(cm³)
25m³ is the smallest among the others.
<span>The hybridization of bromine must be sp^3.</span>
