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navik [9.2K]
3 years ago
10

What is the hydronium ion concentration in an aqueous hydrobromic acid solution with a pH of 4.530?

Chemistry
1 answer:
Aloiza [94]3 years ago
4 0

Answer:

2.951 × 10⁻⁵ M

Explanation:

Let's consider the acid reaction of hydrobromic acid according to Brönsted-Lowry acid-base theory.

HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)

Given the pH = 4.530, we can calculate the concentration of the hydronium ion using the following expression.

pH = -log [H₃O⁺]

[H₃O⁺] = antilog -pH = antilog -4.530 = 2.951 × 10⁻⁵ M

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Question 5
bagirrra123 [75]

Answer:

true

Explanation:

any object that is larger will take a longer time to do things, the same applies to heat levels. The lower the heat, the longer it takes, the higher the heat, the shorter it takes. So if an iceberg is large, it will need a higher heat, whereas an ice cube is really small and doesn't need that much heat to melt.

3 0
3 years ago
D) does not dissociate in solution.
natima [27]

Answer:

According to the proton theory of acids and bases by J. Brønsted and T. Lowry, the  acid is<u> proton donor</u>.

Explanation:

According to the Bronsted lowry concept an acid is substance that gives protons or hydrogen ion while,

Base is substance that accept hydrogen ion or proton.

Consider the following example:

NH₃ + HCl  →  NH₄⁺ + Cl⁻

In this example HCl is Bronsted lowry acid it gives H⁺ while ammonia is Bronsted lowry base because it accept H⁺.

This also gives the concept of conjugate acid and base. In given example Cl⁻ is conjugate base of HCl while NH₄⁺ is conjugate acid of ammonia.

4 0
3 years ago
L = 5 m, w = 1 m, h = 3 m<br><br> 15 m3<br> 5 m2<br> 30 m2<br> 9 m3<br> 7.5 m3
melomori [17]

Volume of Cuboid :

  • l × w × h

  • 5 × 1 × 3

  • 15 m³
6 0
2 years ago
Zinc and hydrochloric acid react to form zinc chloride and hydrogen gas according to
stealth61 [152]

Explanation:

Mole ratio of Zn to HCl = 1 : 2.

If we use all 2.0mol of Zn, we would need 2.0 * 2 = 4.0mol of HCl. However we only have 3.0mol of HCl.

Therefore HCl is limiting.

6 0
3 years ago
What is the engine piston displacement in liters of an engine whose displacement is listed as 490 in^3?
marishachu [46]

Answer:

490 in^3 = 8.03 L

Explanation:

Given:

The engine displacement = 490 in^3

= 490 in³

To determine the engine piston displacement in liters L;

(NOTE: Both in^3 (in³) and L are units of volume). Hence, to find the engine piston displacement in liters (L), we will convert in^3 to liters (L)

First, we will convert in³ to cm³

Since 1 in = 2.54 cm

∴ 1 in³ = 16.387 cm³

If 1 in³ = 16.387 cm³

Then 490 in³ =  (490 in³ × 16.387 cm³) / 1 in³ = 8029.63 cm³

∴ 490 in³ = 8029.63 cm³

Now will convert cm³ to dm³

(NOTE: 1 L = 1 dm³)

1 cm = 1 × 10⁻² m = 1 × 10⁻¹ dm

∴ 1 cm³ = 1 × 10⁻⁶ m³ = 1 × 10⁻³ dm³

If 1 cm³ = 1 × 10⁻³ dm³

Then, 8029.63 cm³ = (8029.63 cm³ × 1 × 10⁻³ dm³) / 1 cm³ = 8.02963 dm³

≅ 8.03 dm³

∴ 8029.63 cm³ = 8.03 dm³

Hence, 490 in³ = 8029.63 cm³ = 8.03 dm³

Since 1L = 1 dm³

∴ 8.03 dm³ = 8.03 L

Hence, 490 in³ = 8.03 L

3 0
2 years ago
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