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sweet [91]
3 years ago
12

Nistu is cooking rice in a pot. When she leaves the pot on the stove for a while, the temperature of the rice increases. What ha

ppens to the molecules of the rice when the temperature of the rice increases?
Chemistry
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

The energy of the molecules in the rice increases.

Explanation:

Mila [183]3 years ago
5 0

Answer:

Their average kinetic energy increases

Explanation:

The average kinetic energy of the rice molecules increases as the pot is left on the cooking stove.

Heat is transferred to the pot by conduction from the heat source. The heat is then transferred to the rice in the cooking pot by convection.

  • As the water in the pot heats up.
  • The rice gains thermal energy.
  • This causes the molecules of the rice particles to start vibrating.
  • As the molecules vibrate about their fixed position, their thermal energy continues to increase.
  • Therefore, the amount of heat absorbed by the rice increases with time and this actually cooks the food.
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What is manganese dioxide in preparation of oxygen?
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Answer:

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An unknown liquid has a mass of 22.1 g
Yuki888 [10]
M = 22.1 g
V = 52.3 mL
D = ?

D = m/V
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6 0
3 years ago
what is the percent yield of NaCl if 31.0 g of CuCl reacts with excess NaNo3 to produce 21.2 g of NaCl
olchik [2.2K]
Percentage Yield = (Actual Yield ÷ Theoretical Yield) × 100  

The Actual Yield is given in the question as 21.2 g of NaCl.  However, in order to find the theoretical yield, you have to write a balanced equation and use the mole ratio to calculate the mass of NaCl that would be produced.

Balanced Equation:   CuCl + NaNO₃    →    NaCl + CuNO₃

Moles of CuCl = Mass of CuCl ÷ Molar Mass of CuCl
                         =  31.0 g ÷ (63.5 + 35.5)g/mol
                         = 0.31 mol

the mole ratio of CuCl to NaCl is 1  :  1,
∴ if moles of CuCl = 0.31  mol,

then moles of NaCl = 0.31 mol

Now, Mass of NaCl = Moles of NaCl × Molar Mass of NaCl
                                 =  0.31 mol × (23 + 35.5) g/mol
                                 =  18.32 g

⇒ the THEORETICAL Yield of NaCl, in this case, is 18.32 g.

Now, since Percentage Yield = (Actual Yield ÷ Theoretical Yield) × 100  

⇒ Percentage Yield of NaCl = (21.2g ÷ 18.32g) × 100  
                                                = 115.7 %


NOTE: Typically, the percentage yield of a reaction is less than 100%, however in a case where the mass of the substance is weighed with impurities, then that mass may be in excess of 100% as seen here.
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