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sweet [91]
3 years ago
12

Nistu is cooking rice in a pot. When she leaves the pot on the stove for a while, the temperature of the rice increases. What ha

ppens to the molecules of the rice when the temperature of the rice increases?
Chemistry
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

The energy of the molecules in the rice increases.

Explanation:

Mila [183]3 years ago
5 0

Answer:

Their average kinetic energy increases

Explanation:

The average kinetic energy of the rice molecules increases as the pot is left on the cooking stove.

Heat is transferred to the pot by conduction from the heat source. The heat is then transferred to the rice in the cooking pot by convection.

  • As the water in the pot heats up.
  • The rice gains thermal energy.
  • This causes the molecules of the rice particles to start vibrating.
  • As the molecules vibrate about their fixed position, their thermal energy continues to increase.
  • Therefore, the amount of heat absorbed by the rice increases with time and this actually cooks the food.
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Compare the root mean square speeds of O2 and UF6 at 65 degree Celsius
gayaneshka [121]
<h3>Answer:</h3>

The root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

<h3>Solution and Explanation:</h3>
  • To find how fast molecules or particles of gases move at a particular temperature, the root  mean square speed is calculated.
  • Root mean square speed of a gas is calculated by using the formula;

       Root mean square=\sqrt{ \frac{3RT}{M}

       Where R is the molar gas constant, T is the temperature and M is the molar mass of gas in Kg.

<h3>Step 1: Root mean square speed from O₂</h3>

Molar mass of Oxygen is 32.0 g/mol or 0.032 kg/mol

Temperature = 65 degrees Celsius or 338 K

Molar gas constant = 8.3145 J/k.mol

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.032}

                                        = 513.289 m/s

<h3>Step 2: Root mean square speed of UF₆   </h3>

The molar mass of UF₆ is 352 g/mol or 0.352 kg/mol        

Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.352}

                                                 = 154.762m/s

Therefore; the root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

7 0
3 years ago
Equilibrium describes the balance that results from a forward and reverse reaction proceeding at equal rates. Since reaction rat
Delvig [45]

Answer:

b) the reaction proceeds to a new equilibrium in the direction that offsets the change.

Explanation:

According to Le Chatelier's principle, when a system experiences a constraint such as a change in pressure, temperature or concentration, the system will readjust itself in order to annul the constraint.

This simply means that when temperature, concentration or pressure is changed, a new equilibrium position is reached in order to offset the changes in the system.

5 0
3 years ago
Are hydrocarbons approved for retrofit applications
Alborosie
Yes they are what are your options
3 0
3 years ago
Which pair of elements would most likely form a covalent bond
denpristay [2]

Answer:

Nonmetals and nonmetals tend to form covalent bonds.

or

P and S

Explanation:

5 0
3 years ago
A sample of gas contains 0.1700 mol of NH3(g) and 0.2125 mol of O2(g) and occupies a volume of 17.8 L. The following reaction ta
telo118 [61]

Answer:

The volume of the sample after the reaction takes place is 19.78 L.

Explanation:

The given variables are;

Number of moles of NH₃(g) = 0.1700 mol

Number of moles of O₂(g) = 0.2125 mol

Volume occupied by the mixture = 17.8 L

The reaction

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)

Then takes place

That is 4 moles of NH₃(g) reacts with 5 moles of O₂(g) to produce 4 moles of NO(g) and 6 moles of H₂O(g).

Since there are less number of moles of NH₃(g) (= 0.1700 mol) in the mixture, we factor the above equation by the number of moles of NH₃(g)  present.

That is,

1 moles of NH₃(g) reacts with 5/4 moles of O₂(g) to produce 1 moles of NO(g) and 3/2 moles of H₂O(g).

Therefore,

0.1700 mol of NH₃(g) reacts with 5/4×0.1700  moles of O₂(g) to produce 0.1700  moles of NO(g) and 3/2×0.1700  moles of H₂O(g).

Which gives

0.1700 mol of NH₃(g) reacts with 0.2125  moles of O₂(g) to produce 0.1700  moles of NO(g) and 0.255  moles of H₂O(g).

Therefore, all of the NH₃(g) and O₂(g)  are consumed in the reaction and the present gases in sample then becomes

0.1700  moles of NO(g) and 0.255  moles of H₂O(g).

Total number of moles of reactant = 0.17 + 0.2125 = 0.3825

Total number of moles of product formed = 0.17 + 0.255 = 0.425

However, Avogadro's law states that equal volume of all gases at the same temperature and pressure contains equal number of molecules.

That is volume occupied by  0.3825 moles of gas = 17.8 L

Therefore the volume occupied by  0.425 moles of gas = 17.8×0.425/0.3825 L = 19.78 L

3 0
4 years ago
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