If a mixture containing 0.50 moles of N2 and 1.8 moles of H2 is allowed to react according to the equation N2 3H2 2NH3 Group of
1 answer:
Answer: hydrogen is the limiting reactant.
Explanation:
We have the equation .
This means that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.
- Considering the nitrogen, the reaction can occur 0.50 times.
- Considering the hydrogen, the reaction can occur 1.8/3 = 0.6 times.
Therefore, <u>hydrogen</u> is the limiting reactant.
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Answer:
a) The equilibrium will shift in the right direction.
b) The new equilibrium concentrations after reestablishment of the equilibrium :
Explanation:
a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
On increase in amount of reactant
If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of is increasing .So, the equilibrium will shift in the right direction.
b)
Concentration of = 0.195 M
Concentration of =
Concentration of =
On adding more to 0.370 M at equilibrium :
Initially
0.370 M
At equilibrium:
(0.370-x)M
The equilibrium constant of the reaction =
The equilibrium expression is given as:
On solving for x:
x = 0.0233 M
The new equilibrium concentrations after reestablishment of the equilibrium :