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aliya0001 [1]
1 year ago
14

C. By examining the physical and chemical properties of evidence at a crime scene, investigators can

Chemistry
1 answer:
OLEGan [10]1 year ago
3 0

Answer:

Physical and chemical properties of evidence can pinpoint the cause of unalive, or can identify the unaliver!

Explanation:

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Can someone help me with this please
dusya [7]
Boiling water: It starts bubbling and it becomes hot
Baking Cake: The cake becomes soft and not liquid
Burning Wood: The wood burns and turns into ash
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Hope this helps!
STSN
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3 years ago
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John dalton proposed a theory that all matter is made up of individuals particles which cannot be divided. what were those parti
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3 years ago
4. The volume of a sample of a gas at STP is 200.0 ml. If the pressure is increased to 4.00 atmospheres (temperature constant),
Elina [12.6K]

Answer : The value of new volume is, 50.0 mL

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure at STP = 1 atm

P_2 = final pressure =  4.00  atm

V_1 = initial volume at STP = 200.0 mL

V_2 = final volume = ?

Now put all the given values in the above equation, we get:

1atm\times 200.0mL=4.00atm\times V_2

V_2=50.0mL

Therefore, the value of new volume is, 50.0 mL

6 0
3 years ago
Why does fingernail polish float on top of water?​
7nadin3 [17]
Difference in density between the two liquids
5 0
3 years ago
How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
2 years ago
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