An adiabatic process is when the system is insulated that no heat is released to the surroundings. For this type of process, we have a derived formula written below:
(T₂/T₁)^C = (V₁/V₂)
where C = Cv/nR
From the complete problem shown in the attached picture, Cv = (3/2)R. Thus,
C= (3/2)/1 mol = 3/2
(T₂/305 K)^(3/2) = (8.5 L/82 L)
Solving for T₂,
<em>T₂ = 67.3 K</em>
Answer:
The <em>chemical</em><em> </em><em><u>reaction</u></em><em><u> </u></em><em><u>rate</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>effect</u></em><em><u> </u></em><em><u>that</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>two</u></em><em><u> </u></em><em><u>reactants</u></em><em><u> </u></em><em><u>disolve</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>liter</u></em><em><u> </u></em><em><u> </u></em><em><u>so</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u> </u></em><em><u>pure</u></em><em><u> </u></em><em><u>water</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>added</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>still</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>same</u></em><em><u> </u></em><em><u>reaction</u></em><em><u> </u></em><em><u>but</u></em><em><u> </u></em><em><u>lighter</u></em>
Explanation:
<em>#keep</em><em> </em><em>on</em><em> </em><em><u>learning</u></em>
Answer:
Cell A
Explanation:
Cell A contains chloroplasts, which are only found in plant cells.
For this problem, we use the freezing point depression formula:
Tf,solvent - Tf,solution = Kf×m
Where
Tf,solvent is freezing pt of the solvent
Tf,solution is freezing pt of solution
Kf is the <span>molal freezing point depression constant of the solvent
m is the molality equal to mol solute/kg solvent
For water as solvent, Tf,solvent = 0</span>°C; Kf = 1.86 °C/m:
0°C - ⁻10.5 °C = (1.86 °C/m)(m)
Solving for m,
m = 5.645 mol solute/kg solvent
5.645 = mol solute/1 kg water
mol solute = 5.645 mol fructose
Since the molar massof fructose is 180.16 g/mol,
Mass of Fructose = 5.645 mol * 180.16 g/mol
Mass of Fructose = 1,017.03 g fructose or 1.017 kg fructose
Answer:
Water molecules forming hydrogen bonds with one another. The partial negative charge on the O of one molecule can form a hydrogen bond with the partial positive charge on the hydrogens of other molecules. Water molecules are also attracted to other polar molecules and to ions.
Explanation: Water molecules forming hydrogen bonds with one another. The partial negative charge on the O of one molecule can form a hydrogen bond with the partial positive charge on the hydrogens of other molecules. Water molecules are also attracted to other polar molecules and to ions.