The behavior of light can be modeled as ______

Stolb23 [73]

Answer:

Types of Hydrolysis

There are several types of hydrolysis, and we will look at them in brief below.

Salts: This is the most common type of hydrolysis. Hydrolysis of salts generally refers to the reaction of salt with water where it involves the interaction between cations or anions of salts and water. During hydrolysis, a salt breaks down to form ions, completely or partially depending upon the solubility factor.

Acid and Base: Acid–base-catalysed hydrolysis can be found during the hydrolysis of esters or amides. Here, the process of hydrolysis occurs when water or hydroxyl ion reacts with the carbon of the carbonyl group of the ester or amide where new compounds are formed. The products of both hydrolysis are compounds with carboxylic acid groups.

ATP: Most biochemical reactions that occur in living organisms are in the form of ATP hydrolysis which takes place with the help of enzymes acting as catalysts. The catalytic action of enzymes allows the hydrolysis or breaking down of proteins, lipids, oils, fats and carbohydrates.

Explanation:

8 0

3 years ago

A sample of sodium sulfite has a mass of 2.80 g.

Gnom [1K]

Answer:

For a: The number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

For b: The number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

For c: The mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

Explanation:

The chemical formula of sodium sulfite is $Na_2SO_3$ . It is formed by the combination of 2 sodium $(Na^+)$ ions and 1 sulfite $(SO_3^{2-})$ ions

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sodium sulfite = 2.80 g

Molar mass of sodium sulfite = 126 g/mol

Putting values in above equation, we get:

$\text{Moles of sodium sulfite}=\frac{2.80g}{126g/mol}=0.022mol$

For a:

Moles of sodium ions in sodium sulfite = (2 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(2\times 0.022\times 6.022\times 10^{23})=2.65\times 10^{22}$ number of sodium ions

Hence, the number of sodium ions in given amount of sodium sulfite are $2.65\times 10^{22}$

For b:

Moles of sulfite ions in sodium sulfite = (1 × 0.022) moles

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.022 moles of sodium sulfite will contain = $(1\times 0.022\times 6.022\times 10^{23})=1.325\times 10^{22}$ number of sulfite ions

Hence, the number of sulfite ions in given amount of sodium sulfite are $1.325\times 10^{22}$

For c:

Molar mass of sodium sulfite = 126 g/mol

According to mole concept:

$6.022\times 10^{23}$ number of formula units are present in 1 mole of a compound

Or, $6.022\times 10^{23}$ number of formula units of sodium sulfite have a mass of 126 grams

So, 1 formula unit of sodium sulfite will have a mass of = $\frac{126}{6.022\times 10^{23}}\times 1=2.09\times 10^{-22}g$

Hence, the mass of one formula unit of sodium ions is $2.09\times 10^{-22}$ grams

7 0

3 years ago

Im gonna ride it do it just how you like it and after that let's do it?

Reika [66]

Answer:

the hell?

Explanation:

7 0

3 years ago

Read 2 more answers

Công thức của A có dạng Ca(hco3)x có ptk là 162 tìm x

harina [27]

Answer:

j

Explanation:

nwjwjw

dodkekds

dldldle

5 0

2 years ago

Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i

ankoles [38]

First, we need to get the value of Ka:

when Ka = Kw / Kb

we have Kb = 1.8 x 10^-5

and Kw = 3.99 x 10^-16 so, by substitution:

Ka = (3.99 x 10^-16) / (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

NH4+ + H2O →NH3 + H+
intial 0.013 0 0

change -X +X +X

Equ (0.013-X) X X

when Ka = [NH3][H+] / [NH4+]

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X) by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]

= -㏒(5.35 x 10^-7)
= 6.27

6 0

3 years ago

The behavior of light can be modeled as _______.