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kvv77 [185]
3 years ago
6

A 143.1 g sample of a compound contains 53.4 g of carbon, 16.9 g of hydrogen, 43 g of nitrogen, and some amount of oxygen. what

is the mass percent of oxygen in the compound? 11.20% 11.81% 20.82% 30.05% 37.34%
Chemistry
2 answers:
nika2105 [10]3 years ago
6 0
I'm fairly sure this is it 20.82%
dalvyx [7]3 years ago
6 0

Answer:

20.82% is the mass percent of oxygen in the compound.

Explanation:

Total mass of the compound = 143.1 g

Mass of carbon = 53.4 g

Mass of hydrogen = 16.9 g

Mass of nitrogen= 43 g

Mass of oxygen= x

143.1 g = x + 53.4 g + 16.9 g + 43 g

x = 143.1 g - 53.4 g - 16.9 g - 43 g = 29.8 g

Percentage of oxygen in the compound:

\%=\frac{\text{Mass of oxygen}}{\text{Mass of compound}}\times 100

\%=\frac{29.8 g}{143.1 g}\times 100=20.82\%

20.82% is the mass percent of oxygen in the compound.

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A sample of 1.000 g of a compound containing carbon and hydrogen reacts with oxygen at elevated temperature to yield 0.692 g H₂O
ollegr [7]

Answer :

(a) 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) There is no other element present in the compound.

Explanation :

(a) Now we have to determine the masses of C and H in the sample.

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

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We are given:

Mass of CO_2=3.381g

Mass of H_2O=0.692g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.381 g of carbon dioxide, \frac{12}{44}\times 3.381=0.922g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

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Thus, 1.000 g of compound containing carbon and hydrogen is, 0.922 g and 0.0769 g respectively.

(b) Now we have to determine the compound contain any other elements or not.

Mass carbon + Mass of hydrogen = 0.922 g + 0.0769 g = 0.999 g ≈ 1 g

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3 years ago
Love yall hope you doing good also anyone feel free to talk
statuscvo [17]
I’m doing good thanks
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