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Llana [10]
2 years ago
11

A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on the free end of the rope f

or maintaining equilibrium that is required to just support a 5 kN weight. The coefficient of friction between the rope and the cylinder is 0.2
Physics
1 answer:
Taya2010 [7]2 years ago
8 0

The range of force exerted at the end of the rope is 285.7 N to 1,000 N.

<h3>Net horizontal force of the cylinder</h3>

The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.

∑F = 0

F - μFn = 0

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force increases as the number of turns of the rope increases.

minimum force = total force/number of turns of rope

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

Learn more about Newton's second law of motion here: brainly.com/question/3999427

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If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Mrrafil [7]

Answer:

The maximum wavelength is 492 nm.

Explanation:

Given that,

Angular separation \theta=3.0\times10^{-5}\ rad

Suppose a telescope with a small circular aperture of diameter 2.0 cm.

We need to calculate the maximum wavelength

Using formula of angular separation

\sin\theta=\dfrac{1.22\lambda}{d}

\lambda=\dfrac{d\sin\theta}{1.22}

Put the value into the formula

\lambda=\dfrac{2.0\times\sin(3\times10^{-5})}{1.22}

For small angle \sin\theta\approx\theta

\lambda=\dfrac{0.02\times3\times10^{-5}}{1.22}

\lambda=4.92\times10^{-7}\ m

\lambda=492\ nm

Hence, The maximum wavelength is 492 nm.

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3 years ago
What is the order of the electromagnetic spectrum from highest to lowest energy?
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<span> Radio waves, microwaves, infra red, visible light, ultra violet, x-rays, gamma rays. </span>

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4 0
2 years ago
Conduction is usually faster/slower in liquids and certain solids than in gases.
KIM [24]
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6 0
3 years ago
In nuclear reaction 5 kg of reactants give 2kg of products
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6 0
2 years ago
An object experiences a net acceleration to the left. Which of the following statements about this object are true? There may be
dedylja [7]

Answer:

  1. When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
  2. If the mass of the object was doubled, it would experience an acceleration of half the magnitude

Explanation:

When an object experiences acceleration to the left, the net force acting on this object will also be to the left.

From Newton's second law of motion, the acceleration of the object is given as;

a = ∑F / m

a = -F / m

The negative value of "a" indicates acceleration to the left

where;

∑F is the net force on the object

m is the mass of the object

At a constant force, F = ma ⇒ m₁a₁ = m₂a₂

If the mass of the object was doubled, m₂ = 2m₁

a₂ = (m₁a₁) / (m₂)

a₂ = (m₁a₁) / (2m₁)

a₂ = ¹/₂(a₁)

Therefore, the following can be deduced from the acceleration of this object;

  1. When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
  2. If the mass of the object was doubled, it would experience an acceleration of half the magnitude

6 0
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