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AlexFokin [52]
2 years ago
8

Suppose you are walking in an airliner in flight. Use Newton’s third law to describe the effect of your walk on the motion on th

e airliner.
Physics
1 answer:
Novosadov [1.4K]2 years ago
4 0

Answer:

The effect of your walking will create a force on the airline acting downwards, due to the weight. By Newton's thirds law the airline will exert an equal and opposite reaction force directed downwards.

Explanation:

The weight of all the passengers acts downwards on the floor of the Airplane.

The Airplane exerts an equal and opposite force on the passengers, with the help of its propulsion due to which the flight keeps on flying without falling down.

Hence by changing the frame of reference we can observe the force which is responsible for the reaction.

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When are you most aware of your motion in a moving vehicle: when it is moving steadily in a straight line or when it is accelera
Ghella [55]

Answer:

Acceleration is percieved, not constant velocity.

Explanation:

You are most aware when the vehicle is accelerating. At constant velocity you would not be aware of the motion. Only if the system is accelerated the dynamics must be solved considering a pseudo-force (of inertial origin) acting.

It's because of this that:

(A) False. The acceleration can be detected from the inside of a closed car.

(B) False. You would be aware of the motion, but not because humans can sense speed but acceleration.

(C) False. Constant velocity cannot be felt in a closed car.

(D) False. Again, you can't feel constant speed.

6 0
2 years ago
What do MRI and ultrasound have in common as diagnostic imaging techniques? Check all that apply.
Gennadij [26K]

Answer:

low risk for tissue damage

uses radio waves

the last three are not correct

:)

8 0
3 years ago
Read 2 more answers
A certain water wave has a wavelength of 25 m and a frequency of 4.0 Hz. What is its velocity?
babymother [125]
Wave speed = frequency * wavelength
Wave speed = 4 * 25
Wave speed = 100 m/s
8 0
3 years ago
A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.64 10-2 kg/s. the density of the gasoline is 735
Irina18 [472]
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m

Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v =  speed of pumping the gasoline, m/s
Then the mass flow rate is 
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s

Answer:  2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
7 0
3 years ago
Read 2 more answers
The wavelength of light is 5000 angstrom. Express it in nm and m.
Ierofanga [76]

Answer:

1 angstrom = 0.1nm

5000 angstrom = 5000/1 × 0.1nm

<h3>= 500nm</h3>

1 \:  angstrom = 1 \times  {10}^{ - 10} m

5000 angstrom = 5000 × 1 × 10^-10

<h3>= 5 × 10^-7 m</h3>

Hope this helps you

7 0
2 years ago
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