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kvasek [131]
3 years ago
15

Volume can be measured in: A. cubic centimeters. B. centimeters. C. square centimeters.

Physics
2 answers:
Ad libitum [116K]3 years ago
8 0

Answer-

A. cubic centimeters.

Hope this helps!

podryga [215]3 years ago
6 0

Answer:

A. cubic centimeters.

Explanation:

Volume can be measured in:

A. cubic centimeters = volume

centimeter = length.

square centimeters = area

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The ratio of the output work to input force is the _ of the machine ?
Colt1911 [192]
<h3><u>Answer;</u></h3>

Mechanical advantage

<h3><u>Explanation;</u></h3>
  • Mechanical advantage is the ratio of force output from a machine divided by the force input into the machine.
  • Mechanical advantage measures the machine's force-magnifying effect. It is an advantage gained by using simple machines to accomplish work with less effort.
  • The formula is; M.A = output force/ Input force
3 0
3 years ago
Read 2 more answers
Which phase of the Moon occurs when Earth, the Moon, and the Sun lie on the same line?
ss7ja [257]
The answer is B I think.
3 0
3 years ago
If your car runs out of gas and you must push it 250 m to the nearest gas station. How much work is done on the car if it is pus
tankabanditka [31]

Answer:

1750 Joules.

Explanation:

Work done = force * distance

= 7 * 250

= 1750 Joules.

6 0
2 years ago
Consider a small car of mass 1200 kg and a large sport utility vehicle (SUV) of mass 4000 kg. The SUV is traveling at the speed
Karolina [17]

Answer:

63.9 m/s

Explanation:

Parameters given:

Mass of small car, m = 1200 kg

Mass of SUV, M = 4000 kg

Speed of SUV, V = 35 m/s

Their kinetic energy of the small car is equal to the kinetic energy of the SUV, hence:

0.5 * m * v² = 0.5 * M * V²

=> 0.5 * 1200 * v² = 0.5 * 4000 * 35²

600 * v² = 2450000

v² = 2450000/600

v² = 4083.3

=> v = 63.9 m/s

The speed of the small car is 63.9 m/s.

6 0
3 years ago
A conical container of radius 6 ft and height 24 ft is filled to a height of 19 ft of a liquid weighing 64.4 lb divided by ft cu
kobusy [5.1K]

Answer:

Part (i) work required to pump the contents to the​ rim is 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5ft above the​ cone's rim is 426,484.878 lb.ft

Explanation:

The center of mass of a uniform solid right circular cone of height h lies on the axis of symmetry at a distance of h/4 from the base and 3h/4 from the top.

Center mass of the liquid Z = (24-19)ft + 19/4 = 5ft + 4.75ft = 9.75 ft

Mass of liquid in the cone = volume × density (ρ) =  ¹/₃.π.r².h.ρ

where;

r is the radius of the liquid surface = [6*(19/24)]ft = 4.75ft

ρ is the density of liquid = 64.4 lb/ft³

h is the height of the liquid = 19 ft

Mass of liquid in the cone = ¹/₃ × π × (4.75)² × 19 × 64.4 = 28,914.229 lbs

Part (i)  work required to pump the contents to the​ rim

Work required = 28,914.229 lbs × 9.75 ft = 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5 ft above the​ cone's rim

Extra work required = 28,914.229 lb ×  5ft = 144571.145 lb.ft

Total work required = (281,913.733 +  144571.145) lb.ft

                                 = 426,484.878 lb.ft

5 0
3 years ago
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