he force between two long parallel conductors is 15 kg/metre. the conductor spacing is 10 cm. If one conductor carries twice the
current of the other, calculate the current in each conductor.
1 answer:
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Answer:
48.7 J
Explanation:
For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.
In particular:
- The elastic potential energy is maximum when the system is at its maximum displacement
- The kinetic energy is maximum when the system passes through the equilibrium position
Therefore, the maximum kinetic energy of the system is given by:
where
m is the mass
v is the speed at equilibrium position
In this problem:
m = 3.6 kg
v = 5.2 m/s
Therefore, the maximum kinetic energy is:
Answer:
Explanation:
given,
rotational inertia, I = 474.0 kg·m²
decrease in angular velocity
ω₁ = 26.2 rad/s ω₂ = 0 rad/s
time = 204 s
torque = ?
α = 0.128 rad/s²
frictional torque acting by the flywheel is equal to 60.88 N.m