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Alex Ar [27]
3 years ago
5

he force between two long parallel conductors is 15 kg/metre. the conductor spacing is 10 cm. If one conductor carries twice the

current of the other, calculate the current in each conductor.

Physics
1 answer:
Oxana [17]3 years ago
8 0
Hey, I assumed you meant the force between conductors was 15 N/m not kg/m.  

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180 pounds (lb) converts to 81.647 kilograms (kg).
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What is the maximum number of electrons an oxygen atom can hold in its outer energy level?
gulaghasi [49]
The answer is 8. 
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An 80-kg man is skating northward and happens to suddenly collide with a 20-kg boy who is ice skating toward the east. Immediate
Fantom [35]

Answer:

6.25 m/s

Explanation:

mass of man (m1) = 80 kg

mass of boy (m2) = 20 kg

mass of man and boy after collision (m12)= 20 + 80 = 100 kg

velocity of man and boy after collision (v) = 2.5 m/s

angle θ = 60 °

How fast was the boy moving just before the collision ?

  • From the diagram attached, the first image shows the man and the boys motion while the second diagram shows their motion rearranged to form a triangle. With the momentum of the man and the boy forming the sides of the triangle.
  • M₁₂ =  total momentum after collision = m12 x v = 100 x 2.5 = 250
  • Mboy = momentum of the boy before collision = m2 x Velocity of boy
  • Mman = momentum of the man before collision = m1 x velocity of man  
  • from the triangle, cos θ = \frac{Mboy}{M₁₂}

        cos 60 = \frac{Mboy}{250}

        Mboy = 250 x cos 60 = 125

  • recall that momentum of the boy (Mboy) also = m2 x Velocity of boy

        therefore

        125 = 20 x velocity of boy

         velocity of boy = 125 / 20 = 6.25 m/s

4 0
3 years ago
Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.
Kitty [74]
To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²
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If your phone needs to be on a charger for three hours to be fully charged, and the charger draws 2 amps, then how many electron
solong [7]

Answer:

Yes you can. The charging current will be the lowest of the two current ratings of device and charger. The charger and the phone have complex internal circuitry that enable this behaviour.

But using a weaker charger for your phone will only lengthen charging time. And using a stronger charger than that the phone will accept doesn't affect charging at all and only wastes money.

7 0
2 years ago
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