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Gnoma [55]
3 years ago
12

You have 13.0 gallons of gasoline. How many liters is this? (1 gallon equals about 3.79 L.)

Physics
2 answers:
Harlamova29_29 [7]3 years ago
8 0

Answer:

I believe the answer is C

Explanation:

Lunna [17]3 years ago
7 0

For this case we must make a conversion, we have as data that:

1 gallon is equivalent to 3.79 liters

By making a rule of three we have:

1 gallon ------------> 3.79 L

13 gallons --------> x

Where "x" represents the equivalent in liters:

x = \frac {13 * 3.79} {1}\\x = 49.27

So, we have 49.27 liters of gasoline.

Answer:

Option C

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Dust particles in air have a typical mass of 5.0 x 10-16 kg. They undergo irregular motion due to collisions with air molecules.
Mars2501 [29]

Answer:

Rms speed of the particle will be  38.68\times 10^8m/sec

Explanation:

We have given mass of the air particle m=5\times 10^{-16}kg

Gas constant R = 8.314 J/mol-K

Temperature is given T = 27^{\circ}C=273+27=300K

We have to find the root mean square speed of the particle

Which is given by v_{rms}=\sqrt{\frac{3RT}{m}}=\sqrt{\frac{3\times 8.314\times 300}{5\times 10^{-16}}}=38.68\times 10^8m/sec

So rms speed of the particle will be 38.68\times 10^8m/sec

5 0
3 years ago
When the effect of aerodynamic drag is included, the y‐acceleration of a baseball moving vertically upward is au = −g − kv2, whi
alexira [117]

Answer:

Explanation:

The detailed steps and appropriate integration and differentiation is as shown in the attached files.

au = −g − kv2

ad = −g + kv2

3 0
3 years ago
A spherical drop of water carrying a charge of 43 pC has a potential of 540 V at its surface (with V = 0 at infinity). (a) What
almond37 [142]

Explanation:

Given that,

Charge on a spherical drop of water is 43 pC

The potential at its surface is 540 V  

(a) The electric potential on the surface is given by :

V=\dfrac{kq}{r}

r is the radius of the drop

r=\dfrac{kq}{V}\\\\r=\dfrac{9\times 10^9\times 43\times 10^{-12}}{540}\\\\r=7.17\times 10^{-4}\ m

(b) Let R is the radius of the spherical drop, when two such drops of the same charge and radius combine to form a single spherical drop. ATQ,

\dfrac{4}{3}\pi r^3+\dfrac{4}{3}\pi r^3=\dfrac{4}{3}\pi R^3\\\\2r^3=R^3\\\\R=2^{1/3} r

Now the charge on the new drop is 2q. New potential is given by :

V=\dfrac{9\times 10^9\times 43\times 10^{-12}\times 2}{2^{1/3}\times 7.17\times 10^{-4}}\\\\V=856.79\ V

Hence, the radius of the drop is 7.17\times 10^{-4}\ m and the potential at the surface of the new drop is 856.79 V.

5 0
2 years ago
If the car’s speed decreases at a constant rate from 71 mi/h to 50 mi/h in 3.0 s, what is the magnitude of its acceleration, ass
melisa1 [442]

Answer:

The acceleration and the distance are 25200 mi/h² and 0.1008 mi.

Explanation:

Given that,

Initial speed = 71 mi/h

Final speed = 50 mi/h

Time = 3.0 s

(a). We need to calculate the acceleration

Using equation of motion

v=u+at

a=\dfrac{v-u}{t}

Put the value in the equation

a=\dfrac{(50-71)\times3600}{3}

a=-25200\ mi/h^2

Negative sign shows the deceleration.

(b). We need to calculate the distance

Using equation of motion

v^2=u^2+2as

(50)^2=(71)^2+2\times(-25200)\times s

s=\dfrac{(50)^2-(71)^2}{-25200}

s=0.1008\ mi

Hence, The acceleration and the distance are 25200 mi/h² and 0.1008 mi.

8 0
3 years ago
The total mechanical energy of a system is 950 J and the gravitational potential energy is 350 J. What is the kinetic energy?​
romanna [79]

Answer:

<em>The kinetic energy is 600 J</em>

Explanation:

<u>Mechanical Energy</u>

The principle of the conservation of mechanical energy states that the total mechanical energy in a system remains constant as long as the only forces acting are conservative forces.

The mechanical energy is defined as the sum of the potential plus kinetic energies:

E = U + K

Where E is the total mechanical energy, U is the gravitational potential energy and K is the kinetic energy.

Solving for K:

K = E - U

The system described has a total mechanical energy of E=950 J and gravitational potential energy of U=350 J, thus:

K = 950 J - 350 J

K = 600 J

The kinetic energy is 600 J

8 0
3 years ago
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