The answer is 2) 4.7 g/mL because the solid use 17 mL and 80g/17mL is 4,7 g/mL.
Answer: Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass, occupies 22.4 L at STP contains avogadro's number
of particles.
Molecular mass of protein = 480,000 g/mol
Thus 1 mole of protein weighs = 480,000 g
So 27 moles of protein weighs = 
Thus the mass, in grams, of 27 moles of smooth muscle myosin is 12960000 grams
Answer:
could u all help me??
Who was Agamemnon trying to persuade to come fight with him again?
Patroclus
Achilles
Odysseus
Hector
Explanation:
In order to determine if the ion is positively charged or negatively charged
Answer:
0.19M
Explanation:
2A → A2
Rate constant = 0.0265 M–1min–1
Initial concentration = 2.00 M
Final Concentration = ?
time, t = 180min
The formular relating the parameters is given as;
1 / [A] = kt + 1 / [A]o
1 / [A] = 0.0265 * 180 + (1 / 2)
1 / [A] = 4.77 + 0.5
[A] = 1 / 5.27 = 0.19M