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4 years ago

Which formula represents a hydrocarbon? (1) CH3I (3) CH3CH3 (2) CH3NH2 (4) CH3OH

Chemistry

2 answers:

stealth61 [152]4 years ago

5 0

Contains only Carbon and Hydrogen.

(3) CH3CH3

Leviafan [203]4 years ago

4 0

Answer: The correct answer is Option 3.

Explanation:

Hydrocarbon is defined as the species in which a covalent bond is present between only hydrogen and carbon atoms. Presence of only hydrogen and carbon atoms is considered as a hydrocarbon.

From the given options:

Option 1: $CH_3I$

Here, a bond is present between carbon and iodine. Thus, it is not considered as a hydrocarbon.

Option 2: $CH_3NH_2$

Here, a bond is present between carbon and nitrogen. Thus, it is not considered as a hydrocarbon.

Option 3: $CH_3CH_3$

Here, a bond is present between carbon and hydrogen. Thus, it is considered as a hydrocarbon.

Option 4: $CH_3OH$

Here, a bond is present between carbon and oxygen. Thus, it is not considered as a hydrocarbon.

Hence, the correct answer is Option 3.

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the combustion of octane is given in this reaction 2C8H18+2502-----16CO2+18H2 O, identify the limit reagent for this reaction wi

Archy [21]

Answer:

Liming reagent in the given reaction is oxygen.

Explanation:

Mass of octane = 12.85 g

Mass of oxygen = 7.46 g

Molar mass of octane = 114.23 g/mol

Molar mass of oxygen = 32

$Mole=\frac{Mass\;in\;g}{Molar\;mass}$

$No.\;of\;moles\;of\;octane=\frac{12.85}{114.23} = 0.1125\;mol$

$No.\;of\;moles\;of\;oxygen=\frac{7.46}{32} = 0.2331\;mol$

$2C_8H_{18} + 25O_2 \rightarrow 16CO_2 +18H_2O$

According to the reaction, 2 moles of octane requires 25 moles of O2

so, 0.1125 moles of octane requires $0.1125\times \frac{25}{2} = 1.40625\;mol$ of oxygen.

but only 0.2331 mol of oxygen is present.

Hence, oxygen is the limiting reagent

4 0

3 years ago

All the processes that form mountain ranges are known as?

laiz [17]

All the processes that form mountain ranges are known as orogenesis. It is a process where a section of the Earth's lithosphere folds and deforms by compression forming mountain ranges this is due to movements of the tectonic plates. The forces or events that acts to this process are called oregony.

8 0

4 years ago

"Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Alex17521 [72]

Answer:

$\boxed{\text{0.50 mol/L}}$

Explanation:

The balanced equation is

2COF₂ ⇌ CO₂+CF₄; Kc = 9.00

1. Set up an ICE table

$\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}$

2. Solve for x

$K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}$

3. Calculate the equilibrium concentration of COF₂

c = (2.00 - x) mol·L⁻¹ = (2.00 - 1.50) mol·L⁻¹ = 0.50 mol

$\text{The equilibrium concentration of COF$_{2}$ at equilibrium is $\boxed{\textbf{0.50 mol/L}}$}$

Check:

$\begin{array}{rcl}\dfrac{1.50^{2}}{0.50^{2}} & = & 9.00\\\\\dfrac{2.25}{0.25}& = & 9.00\\\\9.00 & = & 9.00\\\end{array}$

OK.

5 0

4 years ago

The ksp of copper(ii) carbonate, cuco3, is 1.4 × 10-10. calculate the solubility of this compound in g/l.

Mekhanik [1.2K]

To solve for the solubility of this compound:Cu ^ + 2 + CO3 ^ -2 = [x] [x] = x^2 1.4 x 10 ^ -10 = x^2 x = 1.1832 x 10 ^ -5 1.1832 x 10 ^ -5 moles/ L x 123.526 g/mol (molar mass) is equals to 1.5 x 10 ^-3 g/L is the solubility of this compound - CuCO3.

8 0

3 years ago

Hypothesize what might occur when two oppositely charged objects (positive & negative) are placed close to each other. What

Irina18 [472]

Answer:

When two oppositely charged objects are brought near each other, a force of attraction is produced between the charges and they become attracted to each other.

If the distance between the two charges were to be increased, the force of attraction between the two charges decreases.

Explanation:

According to Coulombs law, the force of attraction or repulsion between two charges is directly proportional to the magnitude of the charges and inversely proportional to the square of distance of separation between the charges.

Also, a fundamental principle of electrostatics states that like charges repel each other whereas unlike charges attract each other.

From these two laws, it can be deduced that a force of attraction will exist between the two oppositely charged objects when they are brought close ti each other. Also, when the distance of separation between the objects is increased, the magnitude of attractive force between them decreases. This decrease is such that if the distance of separation is increased by a factor of say 2, the magnitude of attractive force decreases by a factor of the square of 2 which is 4.

3 0

3 years ago