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Lelechka [254]
4 years ago
5

Which formula represents a hydrocarbon? (1) CH3I (3) CH3CH3 (2) CH3NH2 (4) CH3OH

Chemistry
2 answers:
stealth61 [152]4 years ago
5 0
Contains only Carbon and Hydrogen.

(3) CH3CH3
Leviafan [203]4 years ago
4 0

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

Hydrocarbon is defined as the species in which a covalent bond is present between only hydrogen and carbon atoms. Presence of only hydrogen and carbon atoms is considered as a hydrocarbon.

From the given options:

<u>Option 1:</u> CH_3I

Here, a bond is present between carbon and iodine. Thus, it is not considered as a hydrocarbon.

<u>Option 2:</u> CH_3NH_2

Here, a bond is present between carbon and nitrogen. Thus, it is not considered as a hydrocarbon.

<u>Option 3:</u> CH_3CH_3

Here, a bond is present between carbon and hydrogen. Thus, it is considered as a hydrocarbon.

<u>Option 4:</u> CH_3OH

Here, a bond is present between carbon and oxygen. Thus, it is not considered as a hydrocarbon.

Hence, the correct answer is Option 3.

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3 years ago
Magnesium Oxide decomposes to produce 3.54 grams of oxygen gas. How many grams of magnesium oxide decomposed?
sukhopar [10]
<h2>Let us solve for it </h2>

Explanation:

Magnesium oxide

  • It is MgO  
  • Its molecular mass is : 24 +16=40 g
  • When MgO decomposes it forms = 3.54 g of oxygen gas  
  • when 40 g of MgO decomposes it forms = 16g of oxygen  
  • or we can say that :
  • 16g of oxygen is produced when 40 g of MgO is decomposed .
  • 1g of oxygen will be formed from =40/16g of MgO  
  • 3.54 g of oxygen will be formed = 40/16 x 3.54 =8.85g of MgO  

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What of the following is made out of atoms? (HINT: vocabulary word "atom" or "matter") * 1 Air
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Answer: 4. Active Transport

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3 years ago
Read 2 more answers
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
tino4ka555 [31]

Answer:

2.1 × 10⁻¹ M

2.0 × 10⁻¹ m

Explanation:

Molarity

The molar mass of aniline (solute) is 93.13 g/mol. The moles corresponding to 3.9 g are:

3.9 g × (1 mol/93.13 g) = 0.042 mol

The volume of the solution is 200 mL (0.200 L). The molarity of aniline is:

M = 0.042 mol/0.200 L = 0.21 M = 2.1 × 10⁻¹ M

Molality

The moles of solute are 0.042 mol.

The density of the solvent is 1.05 g/mL. The mass corresponding to 200 mL is:

200 mL × 1.05 g/mL = 210 g = 0.210 kg

The molality of aniline is:

m = 0.042 mol/0.210 kg = 0.20 m = 2.0 × 10⁻¹ m

5 0
3 years ago
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