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3 years ago

Sound travels faster through solids than it does through either liquids or gases a student could verify this statement by

Chemistry

1 answer:

irina [24]3 years ago

4 0

Group of answer choices.

A. Distance that sound travels through a solid, a liquid, and a gas.

B. Pitch of sound when it passes through a solid, a liquid, and a gas.

C. Distance sound travels through a solid, a liquid, and a gas at varying temperatures.

D. Time required for sound to travel a set distance through a solid, a liquid, and a gas.

Answer:

D. Time required for sound to travel a set distance through a solid, a liquid, and a gas.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.

Mathematically, the time required for sound to travel is given by this formula;

$Time = \frac {distance (x)}{speed (v)}$

Hence, the time taken for sound to travel through each medium (solid, liquid and gas) would be measured, recorded and compared to one another.

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Answer:

<h2><u>FAMILY:</u></h2>

Family is defined as a specific group of people that may be made up of partners, children, parents, aunts, uncles, cousins and grandparents. An example of a family is a set of parents living with their children. The definition of family is the group of people who share common ancestors.

<h2><u>IMPORTANCE:</u></h2>

Family is very important part of our everyday life. It helps us in improving our personality. It also helps us in shaping our life. It teaches us the value of love, affection, care, truthfulness and self-confidence and provides us tools and suggestions which are necessary to get success in life. Family is a place where you can be yourself. It is a place where you are accepted for what you are. This is where you are completely tension free and everyone is there to help you. Family encourages you when you are surrounded by problems. It helps you survive through tough times and bring joy and happiness into life.

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3 years ago

Ultrasound and Magnetic Resonance Imaging (MRI), are technologies used to create images of a patient's internal features. In man

Shtirlitz [24]

Its B. I got it right so do B.

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3 years ago

How many moles of cabr2 are in 5.0 grams of cabr2?

worty [1.4K]

Moles of CaBr2 = 5/molar mass of CaBr2
= 5/199.886
= 0.025 moles.

Hope this helps!

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3 years ago

Read 2 more answers

while the substance is a liquid at what temperature do the molecules of the substance have the greatest average kinetic energy

dalvyx [7]

The molecules of the liquid will be having the greatest average kinetic energy when the temperature of the liquid reaches its boiling point.

<u> Explanation: </u>

Average kinetic energy is the measure of kinetic energy exhibited by the molecules of any substance. It is directly proportionate to the temperature of the substance. According to kinetic molecular theory,

$k=\frac{3 R T}{2 N_{A}}$

As the molecules in solids are mostly closely packed, so they will attain the least kinetic energy of molecules in solid phase. Similarly, the molecules in liquid are slightly loosely packed and on increasing the temperature, the molecules will attain more energy to increase their neighbouring distances.

And when that temperature reaches the boiling point of that liquid substance, the molecules had attained the maximum amount of energy to increase its average kinetic energy to the maximum limit and transferring the liquid molecules to gaseous state.

As the molecules in gas phase are very loosely packed. The starting of the change in the state of molecules from liquid to gas phase on reaching the boiling point indicate the maximum average kinetic energy at that point.

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4 years ago

6. A 25.0-mL sample of 0.125 M pyridine is titrated with 0.100 M HCI. Calculate the pH

Vadim26 [7]

Answer:

a) pH = 9.14

b) pH = 8.98

c) pH = 8.79

Explanation:

In this case we have an acid base titration. We have a weak base in this case the pyridine (C₅H₅N) and a strong acid which is the HCl.

Now, we want the know the pH of the resulting solution when we add the following volume of acid: 0, 10 and 20.

To know this, we first need to know the equivalence point of this titration. This can be known using the following expression:

M₁V₁ = M₂V₂ (1)

Using this expression, we can calculate the volume of acid required to reach the equivalence point. Doing that we have:

M₁V₁ = M₂V₂

V₁ = M₂V₂ / M₁

V₁ = 0.125 * 25 / 0.1 = 31.25 mL

This means that the acid and base will reach the equivalence point at 31.25 mL of acid added. So, the volume of added acid of before, are all below this mark, so we can expect that the pH of this solution will be higher than 7, in other words, still basic.

To know the value of pH, we need to apply the following expression:

pH = 14 - pOH (2)

the pOH can be calculated using this expression:

pOH = -log[OH⁻] (3)

The [OH⁻] is a value that can be calculated when the pyridine is dissociated into it's ion. However, as this is a weak acid, the pyridine will not dissociate completely in solution, instead, only a part of it will be dissociated. Now, to know this, we need the Kb value of the pyridine.

The reported Kb value of the pyridine is 1.5x10⁻⁹ so, with this value we will do an ICE chart for each case, and then, calculate the value of the pH.

<u>a) 0 mL of acid added.</u>

In this case, the titration has not begun, so the concentration of the base will not be altered. Now, with the Kb value, let's write an ICE chart to calculate the [OH⁻], the pOH and then the pH:

C₅H₅N + H₂O <-------> C₅H₅NH⁺ + OH⁻ Kb = 1.5x10⁻⁹

i) 0.125 0 0

e) -x +x +x

c) 0.125-x x x

Writting the Kb expression:

Kb = [C₅H₅NH⁺] [OH⁻] / [C₅H₅N] replacing the values of the chart:

1.5x10⁻⁹ = x² / 0.125-x --> Kb is really small, so we can assume that x will be very small too, and 0.125-x can be neglected to only 0.125, and then:

1.5x10⁻⁹ = x² / 0.125

1.5x10⁻⁹ * 0.125 = x²

x = [OH⁻] = 1.37x10⁻⁵ M

Now, we can calculate the pOH:

pOH = -log(1.37x10⁻⁵) = 4.86

Finally the pH:

pH = 14 - 4.86

<u>b) 10 mL of acid added</u>

In this case the titration has begun so the acid starts to react with the base, so we need to know how many moles of the base remains after the volume of added acid:

moles acid = 0.1 * (0.010) = 1x10⁻³ moles

moles base = 0.125 * 0.025 = 3.125x10⁻³

This means that the base is still in higher quantities, and the acid is the limiting reactant here, so the remaining moles will be:

remaining moles of pyridine = 3.125x10⁻³ - 1x10⁻³ = 2.125x10⁻³ moles

The concentration of pyridine in solution:

[C₅H₅N] = 2.125x10⁻³ / (0.025 + 0.010) = 0.0607 M

Now with this concentration, we will do the same procedure of before, with the ICE chart, but replacing this new value of the base, to get the [OH⁻] and then the pH:

C₅H₅N + H₂O <-------> C₅H₅NH⁺ + OH⁻ Kb = 1.5x10⁻⁹

i) 0.0607 0 0

e) -x +x +x

c) 0.0607-x x x

Writting the Kb expression:

Kb = [C₅H₅NH⁺] [OH⁻] / [C₅H₅N] replacing the values of the chart:

1.5x10⁻⁹ = x² / 0.0607-x --> 0.0607

1.5x10⁻⁹ = x² / 0.0607

1.5x10⁻⁹ * 0.0607 = x²

x = [OH⁻] = 9.54x10⁻⁶ M

Now, we can calculate the pOH:

pOH = -log(9.54x10⁻⁶) = 5.02

Finally the pH:

pH = 14 - 5.02

<u>c) 20 mL of acid added:</u>

In this case the titration it's almost reaching the equivalence point and the acid is still reacting with the base, so we need to know how many moles of the base remains after the volume of added acid:

moles acid = 0.1 * (0.020) = 2x10⁻³ moles

moles base = 0.125 * 0.025 = 3.125x10⁻³

This means that the base is still in higher quantities, and the acid is the limiting reactant here, so the remaining moles will be:

remaining moles of pyridine = 3.125x10⁻³ - 2x10⁻³ = 1.125x10⁻³ moles

The concentration of pyridine in solution:

[C₅H₅N] = 1.125x10⁻³ / (0.025 + 0.020) = 0.025 M

Now with this concentration, we will do the same procedure of before, with the ICE chart, but replacing this new value of the base, to get the [OH⁻] and then the pH:

C₅H₅N + H₂O <-------> C₅H₅NH⁺ + OH⁻ Kb = 1.5x10⁻⁹

i) 0.025 0 0

e) -x +x +x

c) 0.025-x x x

Writting the Kb expression:

Kb = [C₅H₅NH⁺] [OH⁻] / [C₅H₅N] replacing the values of the chart:

1.5x10⁻⁹ = x² / 0.025-x --> 0.025

1.5x10⁻⁹ = x² / 0.025

1.5x10⁻⁹ * 0.025 = x²

x = [OH⁻] = 6.12x10⁻⁶ M

Now, we can calculate the pOH:

pOH = -log(6.12x10⁻⁶) = 5.21

Finally the pH:

pH = 14 - 5.21

5 0

3 years ago