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Vera_Pavlovna [14]
3 years ago
11

What is the relationship between resistance and current.

Physics
1 answer:
Tasya [4]3 years ago
7 0

Answer:

They are inversely proportional with each other. R ∝ \frac{1}{I}

Explanation:

By the equation V=IR, assume V is constant.

Since I and R are on the same side,

if I increase, R decreases, or the vice versa.

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Terry says that if an object has no acceleration, then no forces are exerted on it. Sherry doesn't agree, but can't provide an e
crimeas [40]
I say "Terry is correct." and "Stop looking at me !" .
5 0
3 years ago
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An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance
bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 \frac{m}{sec}

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion V^{2} = u^{2} - 2 a s

Put all the values in above formula we get,

⇒ 0 = 0.8^{2} - 2 × a ×0.2667

⇒ a = 1.2 \frac{m}{sec^{2} }

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0
4 years ago
What is the nuclear binding energy in joules for an atom of helium–4? Assume the following: Mass defect = 5.0531 × 10-29 kilogra
Romashka [77]
The equation given, E = mc², can be directly used to determine the unknown amount of nuclear binding energy. Substitute the values given to the equation,
               E = (5.0531 x 10^-29 kg) x (3 x 10^8 m/s)² = 4.548 x 10^-12 J
Thus, the nuclear binding energy is equal to 4.548 x 10^-12 J. 
5 0
4 years ago
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A 5.0-kg block of wood is placed on a 2.0-kg aluminum frying pan. How much heat is required to raise the temperature of both the
Shalnov [3]

Heat required to raise the temperature of a given system is

Q = ms\Delta T

here we know that

m = mass

s = specific heat capacity

\Delta T = change in temperature

now as we know that

mass of wood = 5 kg

mass of aluminium pan = 2 kg

change in temperature = 45 - 20 = 25 degree C

specific heat capacity of wood = 1700 J/kg C

specific heat capacity of aluminium = 900 J/kg C

now here we will find the total heat to raise the temperature of both

Q = m_1s_1\Delta T_1 + m_2s_2\Delta T_2

Q = 5 * 1700 * 25 + 2 * 900 * 25

Q = 212500 + 45000

Q = 257500 J

So heat required to raise the temperature of the system is 257500 J

4 0
3 years ago
One end of a string 6.26 m long is moved up and down with simple harmonic motion at a frequency of 95 Hz . The waves reach the o
uranmaximum [27]

Answer:

Explanation:

Given

length of string L=6.26\ m

frequency f=95\ Hz

time taken by wave to reach at other end t=0.5\ s

speed of  wave is given by

v=\frac{length\ of\ string}{time\ taken}

v=\frac{6.26}{0.5}

v=12.52\ m/s

wavelength of is given by

\lambda =\frac{velocity}{frequency}

\lambda =\frac{12.52}{95}

\lambda =0.131\ m                          

4 0
3 years ago
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