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4 years ago

A spaceship accelerates from 0m/s to 40m/s in 5 seconds. What is the acceleration of the spaceship

Physics

1 answer:

nadya68 [22]4 years ago

6 0

Acceleration = change in velocity/time
= 40/5
=8m/s^2

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Suppose you wanted to improve a moving.coil microphone so that it was more sensitive (e, so that it outputs a stronger induced e

Ne4ueva [31]

Answer:

d. All of the above .

Explanation:

The sensitivity of microphone will be more if even feeble sound can create greater vibration in diaphragm . Naturally it is possible if diaphragm is light and can move easily . The movement it it is controlled by current in the coil which makes it electromagnet . All factors that increase the strength of magnet like increasing the no of turns , or a strong magnet will increase the sensitivity.

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4 years ago

In a double-slit experiment, it is observed that the distance between adjacent maxima on a remote screen is 1.0 cm. What happens

kobusy [5.1K]

Answer:

C) It increases to 2.0 cm

Explanation:

In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by

$\Delta y = \frac{\lambda D}{d}$

where

$\lambda$ is the wavelength of the wave

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is

$d'=\frac{d}{2}$

Substituting into the equation, we find that the new separation between the maxima is

$\Delta y' = \frac{\lambda D}{d/2}=2(\frac{\lambda D}{d})=2\Delta y$

So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.

5 0

3 years ago

Which of the following is true about a combustion reaction?

Ksenya-84 [330]

Answer:

Explanation:

this is because inoder. for combustion or burning to take place oxygen must be available

7 0

3 years ago

Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml

Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}$

$E=2.41\times10^{3}\ V/m$

Hence, The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

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4 years ago

A wave has a frequency of 450 Hz and a wave length of 00.52 m what is the speed of the wave?

nata0808 [166]

Wave speed is always (frequency) x (wavelength)

Speed = (450 /sec) x (0.52 m)

= 234 m/sec .

4 0

3 years ago

Read 2 more answers