3 years ago

Which until is commonly used to measure density

2 answers:

7 0

The correct answer would be : kg/m^3 and the cgs unit of gram per cubic centimetre (g/cm^3)

I hope that this helps you !

Ivenika [448]3 years ago

6 0

Separate mass and volume

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Fiesta28 [93]

Kinetic energy = mass time squared speed divided by 2
W=mv^2/2 = 50*10*10/2 = 2500 J

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3 years ago

Complete the table. can I please get help will give points to whoever

MA_775_DIABLO [31]

Answer: proton mass 1 and neutron has no mass number

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2 years ago

Sam travels west for 30 kilometers, then turns south and travels another 45 kilometers. What is Sam's displacement from his orig

Gre4nikov [31]

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2 years ago

Determine the normal boiling point of a substance whose vapor pressure is 55.1 mm hg at 35°c and has a δhvap of 32.1 kj/mol.

Novosadov [1.4K]

Answer:

389.78681 K

Explanation:

$P_1$ = Initial pressure = 55.1 mmHg

$P_2$ = Final pressure = 1 atm = 760 mmHg

$T_2$ = Boiling point

$T_1$ = Initial temperature = 35°C

$\Delta H_{vap}$ = Heat of vaporization = 32.1 kJ/mol

From the Clausius-Claperyon equation

$ln\dfrac{P_2}{P_1}=(-\dfrac{\Delta H_{vap}}{R})(\dfrac{1}{T_2}-\dfrac{1}{T_1})\\\Rightarrow \dfrac{1}{T_2}=-ln\dfrac{P_2}{P_1}\dfrac{R}{\Delta H_{vap}}+\dfrac{1}{T_1}\\\Rightarrow \dfrac{1}{T_2}=-ln\dfrac{760}{55.1}\dfrac{8.314}{32.1\times 10^{3}}+\dfrac{1}{273.15+35}\\\Rightarrow T_2=\left(-ln\left(\frac{760}{55.1}\right)\frac{8.314}{32.1\times \:10^3}+\frac{1}{273.15+35}\right)^{-1}\\\Rightarrow T_2=389.78681\ K$

The normal boiling point of the substance is 389.78681 K

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3 years ago

2. Après avoir déterminé l'intervalle

SpyIntel [72]

Answer:

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Explanation:

8 0

2 years ago