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Kryger [21]
3 years ago
5

Along boundaries plates are brittle and the crust fractures (breaks and cracks) forming ___

Physics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

Along boundaries plates are brittle and the crust fractures (breaks and cracks) forming Faults

Explanation:

Brittle material are substances that looks hard but can be easily broken by strain. Brittle deformation leads to crack and fracture of the material involve. Brittle crust lacks elastic ability , elasticity in this rocks are almost absent.

Fractures and cracks in rocks form fault. Fault is a discontinuity in rocks with an appreciable displacement. Fault is a displacement in rocks relative to one part. Generally, Fault occur when brittle rock fracture or crack, the fractured rocks move relative to one another.

Differential stress can cause rocks to fracture. If that part of the crust lacks ductility the stress on the rock will cause a brittle deformation. The brittle deformation causes fracture(breaks and cracks) leading to structure like Faults and Joints.    

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If you run at 12 m/s fr 15 minutes, how far will you go
notsponge [240]

Answer:

180m

Explanation:

We can use the formula [ d = st ].

12 * 15 = 180m

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4 0
2 years ago
Using a density of air to be 1.21kg/m3, the diameter of the bottom part of the filter as 0.15m (assume circular cross-section),
salantis [7]

Answer:

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Explanation:

From the question we are told that

     The density of air is  \rho_a  = 1.21 \ kg/m^3

     The diameter of bottom part is  d = 0.15 \ m

The  power trend-line  equation is mathematically represented as

      F_{\alpha }  = 0.9226 * v^{0.5737}

let assume that the velocity is  20 m/s

Then

      F_{\alpha }  = 0.9226 * 20^{0.5737}

       F_{\alpha }  = 5.1453 \ N

The drag coefficient is mathematically represented as

      D_z  =  \frac{2 F_{\alpha } }{A \rho v^2 }

Where  

     F_{\alpha } is the drag force

      \rho is the density of the fluid

       v is the flow velocity

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       A = \pi r^2 =  \pi  \frac{d^2}{4}

substituting values

     A =  3.142 *    \frac{(0.15)^2}{4}

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Then

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3 0
3 years ago
Rubber rods charged by rubbing with cat fur repel each other. Glass rods charged by rubbing with silk repel each other. A rubber
puteri [66]

Answer:

C. A rubber rod and a glass rod charged this way have opposite charges on them.

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When you then try to bring two rubber rod's together, they repel because like charges repel.

Meanwhile, when you rub a glass rod against silk, it loses electrons to the silk material and becomes positively charged.

When you bring two positively charged glass rod's together, they repel, because like charges repel.

However, when you bring the rubber rod and a glass rod together, the attract each other because unlike/opposite charges attract.

5 0
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A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, wha
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