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umka2103 [35]
3 years ago
10

The Sun's angular diameter is measured to be 1920''.The distance D of the Sun from the Earth is 1.496×10^11 m.What is the diamet

er of the Sun?​
Physics
1 answer:
insens350 [35]3 years ago
8 0

The Sun's angular diameter is measured to be

The distance of the sun from the earth is 1.496 × m.

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For the vectors in the figure, with a = 16, b = 12, and c = 20 what are (a) the magnitude and (b) the direction of
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Probably need to see the figure, although a=4x4, b = 3x4, c=5x4 which suggests to me that the figure might be a 3,4,5 right angled triangle ?
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e-lub [12.9K]

Answer:

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Explanation:

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Two particles have a mass of 8kg and 12kg, respectively. if they are 800mm apart, determine the force of gravity acting between
natima [27]
The magnitude of the force of gravity acting between the particles is:
F=G\frac{m_1.m_2}{d^2} 
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P=mg
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P_1=m_1.g=78.48N
P_2=m_2.g=117.72N
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Answer:

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A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak
GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg          

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.  

From the attached figure, the x and y component of forces is given by :

T_{1x} =-T_1 cos (20)

T_{2x} = T_2 cos (40)

mg_x = 0

T_{1y} = T_1 sin (20)

T_{2y} = T_2 sin (40)

mg_y= -mg

Let R_x and R_y is the resultant in x and y direction.

R_x=-T_1 cos (20)+T_2 cos (40)+0

R_y=T_1 sin(20)+T_2 sin(40)-mg

As the system is balanced the net force acting on it is 0. So,

-T_1 cos (20)+T_2 cos (40)+0=0.............(1)

T_1 sin(20)+T_2 sin(40)-100\times 9.8=0..................(2)

On solving equation (1) and (2) we get:  

T_1=866.86\ N (tension on the left rope)

T_2=1063.36\ N (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.                            

7 0
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