Analysis: (use a separate sheet of paper)
1 answer:
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a)
Consider the motion of Al :
v₀ = initial speed of Al = 0.75 m/s
d = distance to be traveled to reach the end of trail = 35 m
a = acceleration = 0.50 m/s²
t = time of travel
Using the equation
d = v₀ t + (0.5) a t²
inserting the values
35 = (0.75) t + (0.5) (0.50) t²
t = 10.4 sec
So Al reach the end of trail after 10.4 sec
b)
Consider the motion of Bert :
x = distance traveled by Bert when Al reach the end = ?
= speed of Bert = 0.75 m/s
t = time of travel = 10.4 sec
Distance traveled by Bert when Al reach the end is given as
x = t
x = (0.75) (10.4)
x = 7.8
x' = distance remaining to reach the end of trail for Bert = ?
distance remaining to reach the end of trail for Bert is given as
x' = d - x
x' = 35 - 7.8
x' = 27.2 m
= relative velocity of Al with respect to bert = 0.85 + 0.75 = 1.6 m/s
t' = time to meetup
Time to meetup is given as
t' = x' /
t' = 27.2/1.6
t' = 17 sec
c)
L = length of the distance of the two from the end
= speed of AL = 0.85 m/s
t' = time to meetup = 17 sec
length of the distance of the two from the end is given as
L = t'
L = (0.85 (17)
L = 14.45 m