Answer:
Average recoil force experienced by machine will be 200 N
Explanation:
We have give mass of each bullet m = 50 gram = 0.05 kg
There are 4 bullets
So mass of 4 bullets = 4×0.05 = 0.2 kg
Initial speed of the bullet u = 0 m/sec
And final speed of the bullet v = 1000 m/sec
So change in momentum 
Time is given per second so t = 1 sec
We know that force is equal to rate of change of momentum
So force will be equal to 
So average recoil force experienced by machine will be 200 N
An atom. Hope this helped
Answer:
P = 227 N
Explanation:
Assuming the crate is on horizontal ground and subject to a horizontal force.
F = ma
P - μmg = ma
P = m(a + μg)
P = m(v²/2s + μg)
P = 50(4²/(2(5))+ 0.3(9.8))
P = 227 N