Answer:
The given element is Radon because its atomic weight is 222 amu.
Explanation:
Given data:
Percentage of A-219 = 13.92%
Percentage of B-222 = 72.16%
Percentage of C-225 = 13.92%
Atomic weight of element = ?
Solution:
Average atomic mass = (abundance of A isotope × its atomic mass) +(abundance of B isotope × its atomic mass) + (abundance of C isotope × its atomic mass) / 100
Average atomic mass = (13.92×219)+(72.16×222) + (13.92×225)/100
Average atomic mass = 3048.48 + 16019.52 +3132/ 100
Average atomic mass = 22200 / 100
Average atomic mass = 222 amu.
The given element is Radon because its atomic weight is 222 amu.
Answer:
proportional. having a constant ratio. Second law: A body of mass m subject to a net force F undergoes an acceleration a that has the same direction as the force and a magnitude that is directly proportional to the force and inversely proportional to the mass, i.e., unbalanced.
Explanation:
hope it's help
To solve the equation for Mass, rearrange the equation by multiplying both sides timesVolume in order to isolate Mass, then plug in your known values (Density and Volume). Then solve for Mass.
Word equation - calcium + oxygen -> calcium oxide
Chemical equation - Ca + O2 -> CaO2
Hope this helps!
