Answer:
pH = 6.5
Explanation:
pH is the negative log of the hydronium concentration, [H⁺]. Since we are given the concentration, we can just plug it in the following equation:
pH = -log[H⁺] = -log[3.5 x 10^-7 M] = 6.5
Answer:
m = 0.3249 g
Explanation:
First, I'm assuming you have a reaction of mercury(II) oxyde descomposition. If this is the case, then the equation to use is the following:
HgO ---------> Hg + O2
Balancing the equation:
2HgO ----------> 2Hg + O2
This means that 2 moles of HgO reacts to produce 1 mole of O2, so, we first calculate the moles of O2, then, the moles of HgO and finally the mass:
We have the volume of O2, the pressure and temperature, so let's use the ideal gas equation:
PV = nRT
Solving for n:
n = PV/RT
R: 0.082 L atm / K mole
T = 70 + 273 = 343 K
V = 83 / 1000 = 0.083 L
Calculating n:
n = 1 * 0.083 / 0.082 * 343
n = 0.003 moles
as stated before, 2 moles of HgO reacts with 1 mole of oxygen so:
2 moles HgO = 1 moles O2
moles HgO = moles O2 / 2
moles HgO = 0.003 / 2 = 0.0015 moles
Finally, to calculate the mass:
m = n * MM
the molar mass of HgO is 216.59 g/mol, so replacing:
m = 0.0015 * 216.59
m = 0.3249 g
There are three kinds of Hydrogen in 2-methyl-2-butene
The correct question is
How many kinds of hydrogen atoms are present in 2-methyl-2-butene
<h3>What is an atom ?</h3>
Atom was discovered by Dalton's Atomic theory , he predicted that each element consist of large number of a very small thing known as atom.
In the structure of 2-methyl-2-butene there are 3 types oh Hydrogen
1. Attached to the Carbon atom connecting the methyl ion to the butene
2. Connected to the last Carbon atom
3. Connected to the Carbon bond having double bond.
Therefore there are three kinds of Hydrogen in 2-methyl-2-butene.
To know more about Atom
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At STP, it is at 273 K and 1.00 atm.
Use PV=nRT to and solve for n (number of mol of N2)
1.00 atm • 4.40L / 0.08206 Latm/molK • 273 K = 0.196 mol N2
There are two mol of N2 for every two mol of NH4NO2 (the number of mol of both are equal)
Find the molar mass of NH4NO2 = 64.1 g
Multiply the number of mol by the molar mass
0.196 mol • 64.1 = 12.6 g NH4NO2