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Sergeeva-Olga [200]
2 years ago
5

A diffraction-limited laser of length L and aperture diameter 0.50 cm generates light of wavelength 700nm . If the beam is direc

ted at the surface and the radius of the illuminated area on the surface is approximately 45cm, how far away is the surface
Physics
1 answer:
Hoochie [10]2 years ago
4 0

The distance of the surface illuminated by the light of the given wavelength is 5,269.32 m.

<h3>Distance of the surface</h3>

The distance of the surface illuminated by the light of the given wavelength is calculated as follows;

D = (rd)/(0.61λ)

where;

  • r is the radius of the illuminated area = 45 cm = 0.45 m
  • d is the diameter of the diameter = 0.5 cm = 0.005 m
  • λ is wavelength = 700 nm = 700 x 10⁻⁹ m

D = (0.45 x 0.005) / (0.61 x 700 x 10⁻⁹)

D = 5,269.32 m

Thus, the distance of the surface illuminated by the light of the given wavelength is 5,269.32 m.

Learn more about wavelength here: brainly.com/question/10728818

#SPJ1

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A driven RLC circuit is being driven by an AC emf source with a maximum current of 2.75 A and maximum voltage of 150 V. The curr
weqwewe [10]

Answer:

(a). Z = 54.54 ohm

(b). R = 36 ohm

(c). The circuit will be Capacitive.

Explanation:

Given data

I = 2.75 A

Voltage = 150 V

\phi = 0.85 rad = 48.72°

(a). Impedance of the circuit is given by

Z = \frac{V}{I}

Z = \frac{150}{2.75}

Z = 54.54 ohm

(b). We know that resistance of the circuit is given by

R = \frac{Z}{\sqrt{1 + \tan^{2}\phi } }

Put the values of Z & \phi in above formula we get

R = \frac{54.54}{\sqrt{1 + \tan^{2} ( \ 48.72) } }

R = 36 ohm

(c). Since the phase angle is negative so the circuit will be Capacitive.

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A chef fills 50ml container with 43.5 g of cooking oil. what is the density of the oil?
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Answer:

0.87 g per ml

Explanation:

D=M/V

43.5/50=0.87

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3 years ago
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Answer is B raindrops conduct electricity from clouds to the ground.
Lightning is formed when air, water droplets, and even ice crystals rub violently against each other inside a thundercloud, creating two opposite kinds of electrical charge
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If you see ##### in a cell, you should
Sveta_85 [38]

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it's D. Make the column wider

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5 0
3 years ago
A ball is dropped from rest at point O. After falling for some time, it passes by a window of height 3.3 m and it does so in 0.2
stiv31 [10]

Answer:

Speed at which the ball passes the window’s top = 10.89 m/s

Explanation:

Height of window = 3.3 m

Time took to cover window = 0.27 s

Initial velocity, u = 0m/s

We have equation of motion s = ut + 0.5at²

For the top of window (position A)

                     s_A=0\times t_A+0.5\times 9.81t_A^2\\\\s_A=4.905t_A^2

For the bottom of window (position B)

                     s_B=0\times t_B+0.5\times 9.81t_B^2\\\\s_A=4.905t_B^2

\texttt{Height of window=}s_B-s_A=3.3\\\\4.905t_B^2-4.905t_A^2=3.3\\\\t_B^2-t_A^2=0.673

We also have

                 t_B-t_A=0.27

Solving

         t_B=0.27+t_A\\\\(0.27+t_A)^2-t_A^2=0.673\\\\t_A^2+0.54t_A+0.0729-t_A^2=0.673\\\\t_A=1.11s\\\\t_B=0.27+1.11=1.38s

So after 1.11 seconds ball reaches at top of window,

       We have equation of motion v = u + at

                                     v_A=0+9.81\times 1.11=10.89m/s

Speed at which the ball passes the window’s top = 10.89 m/s                

7 0
3 years ago
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