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Ilia_Sergeevich [38]
3 years ago
11

Why cant you feel the force attraction between mars

Physics
1 answer:
Ludmilka [50]3 years ago
6 0
The distance is too great for the attraction to make a difference
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How is the pool play helping Adam lift the object
lorasvet [3.4K]
Adam<span> applies and input force to the pulley as he pulls down to </span>lift the object<span>. As he does this, </span>Adam<span>wonders about how the pulley is </span>helping<span> him

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8 0
3 years ago
A spring is compressed 0.035 m inside a dart gun. (K=500 N/m). The spring has elastic energy. Calculate it.
NARA [144]

The elastic potential energy of the spring is 0.31 J

Explanation:

The elastic potential energy of a spring is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the compression/stretching of the spring

For the spring in this problem, we have:

k = 500 N/m (spring constant)

x = 0.035 m (compression)

Substituting, we find the elastic potential energy:

E=\frac{1}{2}(500)(0.035)^2=0.31 J

Learn more about potential energy:

brainly.com/question/1198647

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6 0
3 years ago
You are investigating an elevator accident which happened in a tall building. An elevator in this building is attached to a stro
Advocard [28]

Answer:

a) F = 2250 Ib

b) F = 550 Ib

c) new max force ( F newmax ) = 2850 Ib

Explanation:

A) The force the wall of the elevator shaft exert on the motor if the elevator starts from rest and goes up

max capacity  of elevator = 24000 Ibs

counterweight = 1000 Ibs

To calculate the force (F) :

we first calculate the Tension using this relationship

Counterweight (1000) - T =  ( 1000 / g ) ( g/4 )

Hence T = 750 Ib

next determine F

750 + F - 2400 = 2400 / 4

hence F = 2250 Ib

B ) calculate Tension first

T - 1000 = ( 1000/g ) ( g/4)

T = 1250 Ib

F = 2400 -1250 - 2400/ 4

F = 550 Ib

C ) determine design limit

Max = 2400 * 1.2 = 2880 Ib

750 + new force - 2880 = 2880 / 4

new max force ( F newmax ) = 2850 Ib

8 0
3 years ago
Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30 kg box at the same
Elanso [62]

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

5 0
3 years ago
A 20,000 kg truck traveling at 25 m/s has a head-on inelastic collision with a 1500 kg car traveling at -30 m/s. calculate the i
tankabanditka [31]
Moment is mass times speed
INITIAL moment before collision was 20 000 times 25 = 500 000
7 0
3 years ago
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