The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation f

Question

3 years ago

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The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation f

(x) = ax2 - bx, where a = 65 n/m2, b = 12 n/m, and the positive x direction is in the compression direction of the spring.

Physics

1 answer:

Hoochie [10] · Answer 1 · 2022-07-20T22:22:08+03:00

<span>Answer: F(x) = ax^2 - bx or F(x) = axÂ˛ - bx F(x) = 30xÂ˛ - 6x â«F(x)dx = â«(30xÂ˛ - 6x)dx as this is evaluated from zero to x W = 10xÂł - 3xÂ˛ <===ANS W = 10(0.42Âł) - 3(0.42Â˛) - [10(0Âł) - 3(0Â˛)] W = 0.212 J <===ANS W = 10(0.72Âł) - 3(0.72Â˛) - [10(0.42Âł) - 3(0.42Â˛)] W = 1.966 J <===ANS</span>