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dusya [7]
2 years ago
15

A thin rod of length d on a frictionless surface is pivoted about one end

Physics
1 answer:
motikmotik2 years ago
3 0

The magnitude of the angular momentum of the rod immediately after the collision is given as (pf + pi) * d. (Option A).

<h3>What is Angular Momentum?</h3>

Angular Momentum may be defined or described as the vector quantity of the rotation of a body, which is arrived at by multiplying its moment of inertia by its angular velocity.

The formula for Angular Momentum is given as:

L = <em>mvr; Where

L = Angular Momentum</em>

<em>m = mass</em>

<em>v = velocity; and </em>

<em>r = radius.</em>

Learn more about Angular Momentum at:
brainly.com/question/4126751

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A motorcyclist heading east through a small town accelerate at constant 4.0meter per seconds square after he leaves the limits.
SVETLANKA909090 [29]

A) The position at t = 2.0 sec is 43.0 m east

B) The position is 55 m east

Explanation:

A)

In order to solve the problem, we take the east direction as positive direction.

We know that:

- at t = 0, the motorcyclist is at a position of x_0 = 5.0 m

- at t = 0, the initial velocity of the motorcyclist is v_0 = 15.0 m east

- The acceleration of the motorcyclist is constant and it is a=4.0 m/s^2

Since the motion is a uniformly accelerated motion, the position of the motorcylist is given by the expression

x(t)=x_0 + v_0t + \frac{1}{2}at^2

where t is the time.

Substituting t = 2.0 s, we find the position:

x(2.0)=(5.0)+(15)(2.0)+\frac{1}{2}(4.0)(2.0)^2=43 m

B)

The velocity of the motoryclist can be found by calculating the derivative of the position. Therefore, it is:

v(t)=x'(t)=v_0 + at

where:

v_0=15.0 m/s is the initial velocity

a=4.0 m/s^2 is the acceleration

We want to find the time t at which the velocity is

v = 25 m/s

Solving the equation for t,

t=\frac{v-v_0}{a}=\frac{25-15}{4}=2.5 s

And therefore, the position at t = 2.5 s is:

x(2.5s)=5.0+(15.0)(2.5)+\frac{1}{2}(4)(2.5)^2=55 m

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When you whirl a can at the end of a string in a circular path, what is the direction of the force that acts on the can
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Toward the centre of the circular path

Explanation:

The can is moved in a circular path: this means that it is moving by circular motion (uniform circular motion if its tangential speed is constant).

In order to keep a circular motion, an object must have a force that pushes it towards the centre of the circular trajectory: this force is called centripetal force, and its magnitude is given by

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Predict using Boyle's law, what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.
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The volume of the balloon will halve

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Boyle's law states that for an ideal gas kept at constant temperature, the pressure of the gas is proportional to its volume. Mathematically,

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The equation can also be rewritten as

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And if we apply it to the gas inside the balloon in this problem (assuming its temperature is constant), we have:

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V_2 is the final volume

Substituting into the equation, we find:

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Which means that the volume of the balloon will halve.

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