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2 years ago

A thin rod of length d on a frictionless surface is pivoted about one end

1 answer:

3 0

The magnitude of the angular momentum of the rod immediately after the collision is given as (pf + pi) * d. (Option A).

<h3>What is Angular Momentum?</h3>

Angular Momentum may be defined or described as the vector quantity of the rotation of a body, which is arrived at by multiplying its moment of inertia by its angular velocity.

The formula for Angular Momentum is given as:

L = mvr; Where

L = Angular Momentum

m = mass

v = velocity; and

r = radius.

Learn more about Angular Momentum at:
brainly.com/question/4126751

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Does a wire connected to a dc source, such as a battery, emit an electromagnetic wave?

Lina20 [59]

The wire connected to the DC source doesn't emit electromagnetic waves.

The electromagnetic wave is an oscillation of electric fields and magnets field that sustains each other, this wave time has the characteristics that it can travel without a material medium, for which they are of extreme importance.

It is caused by DC sources such as batteries only having a constant voltage, it is different from AC sources which have different voltage over time, AC voltage can induce the wire because AC sources have magnetic flux change. DC sources don't have magnetic flux change so they don't emit electromagnetic waves.

Learn more electromagnetic waves at: brainly.com/question/25847009

#SPJ4

7 0

2 years ago

Its economics. Its not b. What is it?

Yuliya22 [10]

Answer:

I say this because exponential growth takes place when a population per Capita growth stays the same

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3 years ago

1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wa

love history [14]

Answer:

$ans \: = \boxed{{4.8 \times 10}^{ - 4} Hz}$

Explanation:

$given \to \\ f_{r} = 350 \: \\ v_{r} = {3 \times 10}^{8} \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{r} = \frac{v_{r}}{f_{r}} = \frac{3 \times 10^{8} }{350} = \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\ f_{w} = water \: frequency = \: \boxed{ ?}\: \\ v_{w} = 14 50 \\ but \to \\ v = f \gamma \to \: \gamma = \frac{v}{f} : hence \to \\ \gamma _{w} = \frac{v_{w}}{f_{w}} = \frac{1}{100} \times \gamma _{r} = \frac{1}{100} \times 857,142.85714 \\\gamma _{w} = \boxed{8,571.4285714 \: m} : hence \to \: \\ f_{w} = \frac{v_{w}}{ \gamma _{w}} = \frac{1450}{8,571.4285714} = \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) = \frac{f_{w}}{f_{r}} = \frac{0.1691666667}{350} = 0.0004833333 \\ hence \to \\ the \: frequency \: of \: the \: radio \: wave \: is \to \: \boxed{{4.8 \times 10}^{ - 4} }\: \\ that \: of \: the \: wave \: created \: in \: the \: water.$

♨Rage♨

8 0

3 years ago

A rock group is playing in a bar. Sound

Sloan [31]

Answer:

5292.64 m

Explanation:

$dB \rightarrow \textrm{sound level}\\ I \rightarrow \textrm{sound intensity}\\ I_0 \rightarrow \textrm{threshold sound intensity}\\ x \rightarrow \textrm{distance of corresponding to threshold intensity of hearing}$

Taking threshold intensity as $1\times 10^{-12} W/m^{2}$ and since it's a constant then sound intensity for 66.7 dB will be

$66.7\;\rm dB = 10\; log_{10}\;\left(\dfrac{I}{I_0} \right)\\ \dfrac{I}{10^{-12}} = 10^{6.67}\\ I = 4.67735\times 10^{-6}\;\rm W/m^2\\ \boxed{I \approx 4.7\times 10^{-6}\;\rm W/m^2}$

Also, since sound intensity is inversely proportional to the square of the distance of the source then the distance can be given by

$\dfrac{I_1}{I_2} = \dfrac{r^2_2}{r^2_1}\\ \dfrac{4.7\times 10^{-6}\;\rm W/m^2}{10^{-12}\;\rm W/m^2} = \dfrac{x^2\;\rm m}{(5.96\;\rm m)^2}\\ x =\sqrt{28012000}\\ \boxed{x \approx 5292.64;\rm m}$

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4 years ago

How to revise for science

Scilla [17]

What is your question exactly? im confused

7 0

3 years ago