A thin rod of length d on a frictionless surface is pivoted about one end
1 answer:
The magnitude of the angular momentum of the rod immediately after the collision is given as (pf + pi) * d. (Option A).
<h3>What is Angular Momentum?</h3>
Angular Momentum may be defined or described as the vector quantity of the rotation of a body, which is arrived at by multiplying its moment of inertia by its angular velocity.
The formula for Angular Momentum is given as:
L = <em>mvr; Where
L = Angular Momentum</em>
<em>m = mass</em>
<em>v = velocity; and </em>
<em>r = radius.</em>
Learn more about Angular Momentum at:
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Answer:
6.0 m/s
Explanation:
According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.
Therefore, we can write:
or
where:
m is the mass of the athlete
u is the initial speed of the athlete (at the bottom)
0 is the initial potential energy of the athlete (at the bottom)
v = 0.80 m/s is the final speed of the athlete (at the top)
is the acceleration due to gravity
h = 1.80 m is the final height of the athlete (at the top)
Solving the equation for u, we find the initial speed at which the athlete must jump: